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Solved in 3 steps
- Given the following tRNA anticodon sequence, derive the mRNA and the DNA template strand. Also, write out the amino acid sequence of the protein encoded by this message. tRNA: UAC UCU CGA GGC mRNA: protein: How many hydrogen bonds would be present in the DNA segment?The genetic code is defined as a series of _______________ in _______________. (a) anticodons; tRNA (b) codons; DNA (c) anticodons; mRNA (d) codons; mRNA (e) codons and anticodons; rRNAGiven the following mRNA, write the double-stranded DNA segment that served as the template. Indicate both the 5 and the 3 ends of both DNA strands. Also write out the tRNA anticodons and the amino acid sequence of the protein encoded by the mRNA message. DNA: mRNA: 5-CCGCAUGUUCAGUGGGCGUAAACACUGA-3 protein: tRNA:
- A certain mRNA strand has the following nucleotide sequence: 5AUGACGUAUAACUUU3 What is the anticodon for each codon? What is the amino acid sequence of the polypeptide? (Use Figure 13-5 to help answer this question.) Figure 13-5 The genetic code The genetic code specifies all possible combinations of the three bases that compose codons in mRNA. Of the 64 possible codons, 61 specify amino acids (see Figure 3-17 for an explanation of abbreviations). The codon AUG specifies the amino acid methionine and also signals the ribosome to initiate translation (start). Three codonsUAA, UGA, and UAGdo not specify amino acids; they terminate polypeptide synthesis (stop).The following segment of DNA codes a protein. The uppercase letters represent Exons, the lowercase letters introns. Draw the pre- mRNA, the mature mRNA and translate the codons using the genetic code to form the protein. Identify the 5’UTR and 3UTR 5’- AGGAAATGAAATGCCAgaattgccggatgacGGTCAGCaatcgaGCACATTTGTGATTTACCGT-3’Given the genetic code below, enter the correct amino acid sequence for the following RNA sequence: AUG GAG UCC UUG CUG UGA (enter the amino acids as the 3 letter abbreviation on the table separated by dashes with no spaces e.g. Met-Thr-Lys-Glu-Ser) Alanine (Ala) AGUC Tyrosine (Tyr) Valine (Val) GU Cysteine (Cys) START HERE G Arginine (Arg) G Tryptophan (Trp) A C CUGA Serine (Ser) Leucine (Leu) Lysine (Lys) Proline (Pro) Asparagine (Asn) 0406 ACUGACUOROE (na) auone (aug) Giycine (Gly) Serine (Ser) Phenylalanine Glutamic acid (Glu) Aspartic acid (Asp) Histidine (His) Glutamine (Gin) Arginine (Arg) Isoleucine (lle) Methionine (Met) o Threonine (Thr)
- The DNA in the coding strand below contains a short imaginary sequence for a short protein in Squibillus notables (imaginary bacterial organism). Indicate the mRNA and amino acid sequences. Label the 5' and 3' ends, the amino (N-terminus) and carboxyl (C-terminus) ends and start/stop codons, if present, as appropriate. 5'- ATGTACCTCGACGATCAAGGCAA -3'A segment of a polypeptide chain is Arg-Gly-Ser-Phe-Val-Asp-Arg. It is encoded by the following segment of DNA: GGCTAGCTGCTTCCTTGGGGA CCGATCGACGAAGGAACCCCT Note out the mRNA sequence generated by the template strant to produce that polypeptide chain Label each stran with its correct polarity (5' and 3' ends on each strand)For the messenger RNA sequence below, find the beginning of the amino acid coding sequence and translate the sequence using the genetic code provided below. 5' - AAUUAUGGGCAAUAUGCCGGGCcGGUUAAGCG - 3' Second Letter A UGU cys u UGC Phe UCU UU U UUC UUA UAU Tyr Ser UAC UAA UAG Leu UCA Stop UGA Stop UUG UCG Stop UGG Trp CUU CU CAU His CGU c cuc Leu ccc ССА CCG Pro CÁC CAA CAG CGC CGA CGG Arg CUA CUG Gin 1st 3rd letter Ser u letter AUU ACU AAU AAC AAA AAG Asn A AUC AUA AUG lle ACC ACA AGU AGC AGA AGG Thr Lys Arg Met ACG GUU G GUC GUA GUG GCU GAU GAC GAA Asp GGU Val GCC Ala GGC Gly GCA GGA Glu GCG GAG GGG G
- Use a codon chart determine the amino acid sequence. Remember to read through the strand and ONLY start after the promoter and STOP when it tells you to stop. Follow example below: Example: DNA AGA TATA TAC CTC CGG TGG GTG CTT GTC TGT ATC CTT CTC AGT ATC MRNA O protein AUG GAG GCC ACC CAC GAA CAG ACA UAG GAA GAG UCA UAG start-glu-ala-thre-hist - asp-glu-threo-stop met DNA CCT ATA TAC ACA CGG AGG GTA CGC TAT TCT ATG ATT ACA CGG TTG CGA TCC ATA ATC mRNA DGGA UAU) AUG uGul Gcc nccl cAul GCol protein ly Tur MeT cys AlA ser HIJ Ala 2 3 4 DNA AGA ACT ATA TAC CTC TTA ACA CTC TAA AGA CCA GCA CTC CGA TGA ACT GGA GCA mRNA protein DNA TAT ATAC CTT GGG GAA TAT ACA CGC TGG CTT CGA TGA ATC CGT ACG GTA CTC GCC ATC mRNA protein D DNA TAA ACT ATA TAC CTA GCT TAG ATC TAA TTA CCC ATC mRNA protein Auu UGA UAU AGU GAUCGA AUC MAG Auu AAU leu Stop. TRY-Met-Asp- ARG-Isle-Stop-Ile. Asn DNA CTA TTT ATA TAC TAG AGC GAA TAG AAA CTT ATC ATC mRNA protein D DNA CAT ATA TAC CTT AGT TAT CCA TTG ACT CGA ATT GTG CGC TTG…The codon chart below shows that adenine-uracil-guanine (AUG) codes for the amino acid methionine, and cytosine- adenine-guanine (CAG) codes for glutamine in humans. RNA Codon Chart UCAGUGA Alanine Tyrosine Stop Cystoine Stop Valine G U A GTryptophan Arginine A Leucine Serine Lysine Proline Asparagine ACU lGACU Select the two amino acids that those two codons code for in carrots. O glutamine O isoleucine methionine serine O valine oupne Glycine Phenyl- acid Asparti oartic acid Histidine Glutamine Arginine uauonejos Methionine ThreoninePart of a sequence of DNA from a person without this genetic disease is: TAG TAA AAA CCA CCC AGG Part of a sequence of DNA from a person with a genetic disease is: TAG TAA CCA CCC AGG The possible codons for some amino acids are shown in the table. Amino acid Codons glycine GGU GGC GGA GGG isoleucine AUU AUC phenylalanine UUU UUC serine UCU UCC UCA UCG Which amino acid is missing from a person with this genetic disease? serine glycine O phenylalanine isoleucine