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- Which of the following is an incorrect statement about the bromination of benzene by Br2 and FeBr3? O FeBr3 functions to increase the electrophilicity of Br2. O The carbanioni intermediate is resonance stabilized. O Formation of the sigma complex is the rate-determining step of the mechanism. O There are two carbon-containing intermediates in the mechanism. O The final step of the mechanism is loss of H+. adlanation pollo 8888850 Ber li S SAARISMA Waamowing reactions proceeds via an SN1 or SN2 of the reaction: (b) S2 pro85 39 Br tort atubong auonsV HMPAnoitutitaduaProvide the mechanism for the following reaction (1) PhMgBr (2 equiv) (2) H3O+ workup OH
- The following reaction involves two sequential Heck reactions. Draw structural formu- las for each organopalladium intermediate formed in the sequence and show how the final product is formed. Note from the molecular formula given under each structural formula that this conversion corresponds to a loss of H and I from the starting material. Acetonitrile, CH,CN, is the solvent. 1% mol Pd(OAc), 4% mol Ph,P CH,CN C4H171 C4H16Step 4a: Classify step. The target product is present, but the reaction is not over. The ethoxide ion has been regenerated. :0: :0: What is the key process in the next step of the mechanism? proton transfer formation of a o bond between nucleophile and electrophile loss of a leaving group carbocation rearrangement (e.g., methyl or hydride shift)Identify compounds A and B from the following reaction sequence LINH lig MeO 0 (Ozone) MeOH Me₂S B
- Br Brz CH3 CH3 H3C CH2CI2 H3C Br Electrophilic addition of bromine, Br2; to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH,Cl). In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions Br: :Br: .CH3 H3C H3C CH3 Br:1. The following structure has been used in monitoring the development of amyloid plaques in Alzheimer's patients (J. Med. Chem. 2011, 949). Rank the numbered N atoms in order of increasing pKb value? +0100 2. Provide the structure of the major organic product in the reaction below. Mechanism? CHO H3CO- + CH3NH₂ + H catalyst6. Complete reaction scheme below indicating reagents, catalysts and conditions, and side product trigil bezinslog si6101fon 290b 1l (b Senines levirba 6 gaubong nasamots gniwollot ads to doinW 01 sniowl (6 CH3 40 CH3 Scansgowi (d Ege nodie) ( nsgyxo (b NO₂ 19m02 2i gniwollet sits to mainW II HO
- Draw and name the major product of the reaction (include stereochemistry): OH + SOCI₂ in (Et) 3N Explain the mechanism by which it occurs (SN1, SN₂, E1 or E2).The following reactivity order has been found for the saponification of alkyl acetates by aqueous NaOH. Explain. CH3CO2CH3 > CH3CO2CH2CH3 > CH3CO2CH(CH3)2 > CH3CO2C(CH3)3Draw a structural formula for the major organic product of each reaction and specify the most likely mechanism by which each is formed. (g) CH3CH2ONa++CH2=CHCH2Clethanol