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- b. How many bits are required to address a 4M × 16 main memory if main memory is byte-addressable?c. How many bits are required to address a 1M × 8 main memory if main memory is byte-addressable?0001 = Load AC from memory 0010 = Store AC to memory 0101 = Add to AC from memory 0011 = Load AC (the accumulator register) from an I/O device 0111 = Store AC to an I/O device With these instructions, a particular I/O device is identified by replacing the 12-bit address portion with a 12-bit device number. Remember that a number ending with a small ‘h’ means the number is a hexadecimal number. What is the hexadecimal string that expresses the following instructions? Load AC from memory location 62h. Add the contents of memory location 451h to AC. Store AC to memory location 8h. Store AC to I/O device number 8h.The write operation in Dynamic Random Access Memory (DRAM) is using a voltage signal to represent bit 0 and bit 1. The high voltage represent bit 1 and low voltage represent bit 0? O a. false O b. True
- The contents of memory location B0000, are FF 16, and those at B0001 6 are 0016. What is the data word stored at the address B0000? Is the word aligned or misaligned?What two registers carry the product of two 16-bit values when they are multiplied? The registers with the most and least important components of the product should be shown.If the value 8 is stored in the memory cell corresponding to the address 5, what is the practical difference between writing the value 5 into cell number 6 and copying the contents of cell number 5 into cell number 6?
- 5. Load the register (CL) from the memory location [0500H] then subtract the content of this register from the accumulator (AL). Correct the result as a (BCD) numbers . Let [0500H] = 12H & AL = 3FH %3DWhich of the following statements is correct? I. The 80/20 rule states that 80% of instructions are executed and 20% are created. External bus is used exclusively for data memory in von Neumann architecture II. a) Only I is true; b) Only II is true; c) Both I and I are true; d) Neither I nor II is true.What is the highest and the lowest address in the 8086’s memory address? Is memory in the 8086 microprocessor organized as byte, words or double words ? What is the value of the double word stored in memory starting at address B000316 if the contents of memory location B000316, B000416, B000516 and B000616 are 1116, 2216, 3316 and 4416 respectively ? What is the function of the stack?
- A 74LS139 2-to-4 code is used to partition the memory space of an MC68008 into 4 quadrant, ROM, RAM, PER (for Synchronous devices) and the 4th is reserved for future provision. Write the address range of the RAM. And compute the addresses per location in ROM if is 64 KBDifference between address bus & data bus is: Select one: a. Address bus is bidirectional while data bus Is unidirectional. b. Data wires are only for data signals. C. None of the options given here. d. Both carry bits in either directions. e. Address bus is only for addressing signals.In 8051 assembly language: If one of the elements in a list in ROM is more than 8 bits in binary as shown below list: DB 9H,12H,2021H How can I separate 2021 into 2 bytes in RAM? So that one location in RAM holds 20, and the other 21. (Values in RAM should be in BCD format)