When you substitute y''p and yp into the equation, where does the: 4Ccos(2x) and -4Dsin(2x) come from? While you have 10 different trig functions from the substitution, there should only have been 8 trig finctions from the substitution.... y'' = -9Asin(3x) - 9Bcos(3x) - 4Csin(
When you substitute y''p and yp into the equation, where does the: 4Ccos(2x) and -4Dsin(2x) come from? While you have 10 different trig functions from the substitution, there should only have been 8 trig finctions from the substitution.... y'' = -9Asin(3x) - 9Bcos(3x) - 4Csin(
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section: Chapter Questions
Problem 5T
Question
When you substitute y''p and yp into the equation, where does the:
4Ccos(2x) and -4Dsin(2x) come from?
While you have 10 different trig functions from the substitution, there should only have been 8 trig finctions from the substitution....
y'' = -9Asin(3x) - 9Bcos(3x) - 4Csin(2x) - 4Dcos(2x) --> that's 4
and 4y = 4(Asin(3x) + Bcos(3x) +Csin(2x) + Dcos(2x)) --> that's the other 4.
Where does the 4Ccos(2x) and -4Dsin(2x) come from in the multiplication?
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