Answered: When temperature increases the mean…

When temperature increases the mean free time in a conductor Select one: O a. Oscillates O b. Increases exponentially O c. Decreases O d. Increases O e. Remains the same

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter20: Electric Current, Resistance, And Ohm's Law

Section: Chapter Questions

Problem 58PE: -gauge copper wire has a diameter of 9.266 mm. Calculate the power loss in a kilometer of such wire...

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Question

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When temperature increases the mean free time in a conductor
Select one:
O a. Oscillates
Ob. Increases exponentially
O c. Decreases
d. Increases
O e. Remains the same

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A close analogy exists between the flow of energy by heat because of a temperature difference (see Section 19.6) and the flow of electric charge because of a potential difference. In a metal, energy dQ and electrical charge dq are both transported by free electrons. Consequently, a good electrical conductor is usually a good thermal conductor as well. Consider a thin conducting slab of thickness dx, area A, and electrical conductivity o, with a potential difference dVbetween opposite faces. (a) Show that the current I= dq| dt is given by the equation on the left: Charge conduction Thermal conduction da = GA dt dQ = kA dx dt dx In the analogous thermal conduction equation on the right (Eq. 19.17), the rate dQ/ dt of energy flow by heat (in SI units of joules per second) is due to a temperature gradient dT/ dx in a material of thermal conductivity k. (b) State analogous rules relating the direction of the electric current to the change in potential and relating the direction of energy…
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A close analogy exists between the flow of energy by heat because of a temperature difference (see Section 19.6) and the flow of electric charge because of a potential difference. In a metal, energy dQ and electrical charge dq are both transported by free electrons. Consequently, a good electrical conductor is usually a good thermal conductor as well. Consider a thin conducting slab of thickness dx, area A, and electrical conductivity , with a potential difference dV between opposite faces. (a) Show that the current I = dq/dt is given by the equation on the left: ChargeconductionThermalconductiondqdt=A|dVdx|dQdt=kA|dTdx| In the analogous thermal conduction equation on the right (Eq. 19.17), the rate dQ/dt of energy flow by heat (in SI units of joules per second) is due to a temperature gradient dT/dx in a material of thermal conductivity k. (b) State analogous rules relating the direction of the electric current to the change in potential and relating the direction of energy flow to the change in temperature.
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