When methanol, CH3OH, is burned in the presence of oxygen gas, O₂, a large amount of heat energy is released. For this reason, it is often used as a fuel in high performance racing cars. The combustion of methanol has the balanced, thermochemical equation CH₂OH(g) + O₂(g) · > CO₂(g) + 2 H₂O(1) AH = -764 kJ How much methanol, in grams, must be burned to produce 591 kJ of heat? mass: 50

Chemistry: Principles and Reactions
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Author:William L. Masterton, Cecile N. Hurley
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Chapter8: Thermochemistry
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When methanol, CH₂OH, is burned in the presence of oxygen gas, O₂, a large amount of heat energy is released. For this reason,
it is often used as a fuel in high performance racing cars. The combustion of methanol has the balanced,
thermochemical equation
CH₂OH(g) + O₂(g)
CO₂(g) + 2 H₂O(1) ΔΗ = -764 kJ
How much methanol, in grams, must be burned to produce 591 kJ of heat?
mass:
5.0
g
Transcribed Image Text:When methanol, CH₂OH, is burned in the presence of oxygen gas, O₂, a large amount of heat energy is released. For this reason, it is often used as a fuel in high performance racing cars. The combustion of methanol has the balanced, thermochemical equation CH₂OH(g) + O₂(g) CO₂(g) + 2 H₂O(1) ΔΗ = -764 kJ How much methanol, in grams, must be burned to produce 591 kJ of heat? mass: 5.0 g
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