When a particle is projected vertically upwards with an initial velocity of ϑ0, it experiences an acceleration shown below, where g is the acceleration due to gravity, k is a constant and ϑ is the velocity of the particle. Determine the maximum height reached by the particle in m when k = 0.5 and initial velocity ϑ0 =10 m/s.

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Chapter1: Units, Trigonometry. And Vectors
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Problem 51P: In Problem 50, what is the tangent of the angle for which 5.00 in is the opposite side?
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When a particle is projected vertically upwards with an initial velocity of ϑ0, it experiences an acceleration shown below, where g is the acceleration due to gravity, k is a constant and ϑ is the velocity of the particle. Determine the maximum height reached by the particle in m when k = 0.5 and initial velocity ϑ0 =10 m/s.

a = - (g + kv²),
Transcribed Image Text:a = - (g + kv²),
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