What will be the number of genotypes and phenotypes in F1 (first generation offsprings), if we crossbreed (PPLIRT x PPLIRT) the plants with Purple Large round flowers (PpLIRr) (trihybrid cross)? Both plants are heterozygous for all three traits and the traits behave in a dominant and recessive pattern. Löffen birini seçin: O a. 16 genotypes: 16 phenotypes O b. 81 genotypes; 32 phenotypes O c. 18 genotypes: 8 phenotypes O d. 27 genotypes: 8 phenotypes
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- The hart baowshows mmy trats found in pea plants A botarilst crosses two pure breeding pea plants. one with yellow seeds and one with green seeds, then ose those offspring to produce a F gensration Pea Plant Traits Hower Pod Coler Plant Size Ieated Green Purple G P Green Corstricted Yellow White Terminal Short (Owarf) a Source Pea Plaw Charocienties Mariann Ru Wikimedia Commons What would be the genotypic ratio for seed color in the F 2 generation? O 3 homozygous dominant : 0 heterozygous: 1 homozygous recessive PreviousFor each genotype, indicate whether it is heterozygous (HE) or homozygous (HO) AA Bb Cc Dd Ee ff GG HH PP Pp pp Round seeds are dominant to wrinkled RR Rr rr Ii Jj kk For each of the genotypes below, determine the phenotype. Purple flowers are dominan to white flowers L1 Mm nn straight straight curly 00 Pp Brown eyes are domin BB Bb bb to blue eyes Bobtails are recessive (long tails dominant) TT Tt tt For each phenotype, list the genotypes. (Remember to use the letter of the dominant trait) Straight hair is dominant to curly. Pointed heads are dominant to round heads. pointed pointed roundYou have a purple-flowered pea plant, but you do not know if it is homozygous (PP) or heterozygous (Pp) for flower color because both genotypes result in the same purple phenotype. Purple color allel (P) is dominant over white flower allel (p). What would you do to determine the genotype of flower color of this plant? Lötfen birini seçin: O a. Crossing the plant with homozygous large flowered pea plant (LL) Ob. Crossing the plant with heterozygous purple flowered pea plant (Pp) Crossing the plant with homozygous dominant purple flowered pea plant (PP) d. Crossing the plant with a plant whose genotype is unknown e. Crossing the plant with homozygous recessive white flowered pea plant (pp)
- White fruit color in summer squash is dependent on a dominant gene (W) and colored fruit to the recessive gene (w). In the presence of ww a dominant gene D produces yellow color, but when D is not present, the color is green. Upload your solution in the google classroom. Give the: F1_phenotypes_expected_from_crossing_white_fruited_WWDD_with_green_fruited_wwdd_plant F2_phenotypes_expected_from_crossing_the_F1 F2_phenotypic_ratio_expected_from_crossing_the_F1 F2_genotypic_ratio_expected_from_crossing_the_F1 Type_of_epistatis Write all phenotypes in CAPITAL letters SEPARATED BY COMMA. Write all ratio in numerical values without spacesA researcher studied 6 independently assorting genes in a plant. Each gene has a dominant and a recessive allele: R black stem, r red stem; D tall plant, d dwarf plant; C full pods, c constricted pods; O round fruit, o oval fruit; H hairless leaves, h hairy leaves; W purple flower, w white flower. From the cross Rr Dd Cc Oo Hh Ww (male) x Rr dd Cc oo Hh ww (female): How many different kinds of gametes can be formed from both parents? What is the frequency of obtaining a sperm cell with at 3 dominant and 3 recessive alleles? How many phenotypes are possible among the progeny? How many genotypes? What is probability of obtaining a black, dwarf, constricted, oval, hairy, purple phenotype in the progeny? What is probability of obtaining progeny with exactly same genotype as the female parent? As the male parent? If both parents were heterozygous for all genes, what is the probability of obtaining progeny with at least 2 recessive traits? From the cross in (f), will there be…More Crosses with Pea Plants: The Principle of Independent Assortment Consider the following cross: P1: AABBCCDDEE aabbccddee F1: AaBbCcDdEe (self-cross to get F2) What is the chance of getting an AaBBccDdee individual in the F2 generation?
- In sweet pea plant, an allele for purple flowers (P) is dominant when paired with a recessive allele for red flowers (p). An allele for long pollen grains (L) is dominant when paired with a recessive allele for round pollen grain (l). Bateson and Punnett crossed a plant having purple flowers/long pollen grains with one having white/flowers/round pollen grains. All F1 offspring had purple flowers and long pollen grains. Among the F2 generation, the researchers observed the following phenotypes: 296 purple flowers/long pollen grains 19 purple flowers/round pollen grains 27 red flowers/long pollen grains 85 red flowers/round pollen grains What is the best explanation for these results?More Crosses with Pea Plants: The Principle of Independent Assortment Consider the following cross in pea plants, in which smooth pea shape is dominant to wrinkled, and yellow pea color is dominant to green. A plant with smooth yellow peas is crossed to a plant with wrinkled green peas. The offspring produced peas that were all smooth and yellow. What are the genotypes of the parents? What are the genotypes of the offspring?Figure 8.10 In pea plants, purple flowers (P) are dominant to white (p), and yellow peas (Y) are dominant to green (y). What are the possible genotypes and phenotypes for a cross between PpYY and ppYy pea plants? How many squares would you need to complete a Punnett square analysis of this cross?
- Topic: Trihybrid Cross, Height in merigonias is determined by three unlinked genes that act additively. Each has two alleles, one compltely dominant allele(A,B or C) that makes plants taller and one recessive allele that makes plants shorter. Do the corss AaBbCc X AaBbCc. The fraction of The F1 progenty will be ? Pls explain it with more details. thanksIn pea plants, the tall trait is dominant and the recessive trait is short. What is the GENOTYPE ratio of the following offspring? * T TT Tt Tt tt O 3 Tall: 1 Short 3 TT: 1 tt 3 Short: 1 Tall O 1 TT: 2 Tt: 1 tFruit weight is controlled by 4 gene pairs. The homozygous dominant weights 200 g while the homozygous recessive weighs 80 g. Assume that the alleles have equal contribution and have cumulative effects. The F1 and F2 of the two parents below were studied. Parent 1 Parent 2 B1B1B2B2B3B3b4b4 x b1b1b2b2b3b3B4B4 Provide the genotype and phenotype of the F1.