What volume (in mL) of a 0.125 M HNO3 solution is required to completely react with 25.1 mL of a 0.116 M Na₂CO3 solution according to the following balanced chemical equation? Na₂CO3(aq) + 2 HNO3(aq) → 2 NaNO3(aq) + CO2(g) + H₂O(1) Express your answer with the appropriate units. μÀ V = 11.6464 mL ?

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Chapter4: Chemical Reactions
Section: Chapter Questions
Problem 4.146QP
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You may want to reference (Pages 325-326) Section 8.3 while completing this problem.
Part A
What volume (in mL) of a 0.125 M HNO3 solution is required to completely react with 25.1 mL of a 0.116 M Na₂CO3 solution according to the following balanced chemical equation?
Na2CO3(aq) + 2 HNO3(aq) → 2 NaNO3(aq) + CO₂(g) + H₂O(1)
Express your answer with the appropriate units.
μĂ
V = 11.6464
Submit
mL
P ?
Previous Answers Request Answer
X
Incorrect; Try Again; One attempt remaining
You may have made an improper stoichiometric conversion. According to the balanced chemical equation, each mole of Na2CO3 will react with two moles of HNO3, so the value of 2 should be in
the numerator when calculating the volume of the HNO3 solution.
Transcribed Image Text:You may want to reference (Pages 325-326) Section 8.3 while completing this problem. Part A What volume (in mL) of a 0.125 M HNO3 solution is required to completely react with 25.1 mL of a 0.116 M Na₂CO3 solution according to the following balanced chemical equation? Na2CO3(aq) + 2 HNO3(aq) → 2 NaNO3(aq) + CO₂(g) + H₂O(1) Express your answer with the appropriate units. μĂ V = 11.6464 Submit mL P ? Previous Answers Request Answer X Incorrect; Try Again; One attempt remaining You may have made an improper stoichiometric conversion. According to the balanced chemical equation, each mole of Na2CO3 will react with two moles of HNO3, so the value of 2 should be in the numerator when calculating the volume of the HNO3 solution.
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