What the output ++c
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![What the output ++c
[*] First program.cpp
1
#include <iostream>
Using namespace std;
Main( )
4日{
Int x;
Int y=2;
6.
Int z=3;
(x<y and y<z and x!=z)? cout << "Right" : cout << "Left"
9 - }
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- #include using namespace std3; int main() { int s-4; int d-s++; cout<#include using namespace std; int main() int x=1,y=2; for (int i=0; i<3; i++) e{ x=x*y; 8{ } cout<#177. Run code in C++ compiler #include using namespace std; void square (int *x) { *x = (*x + 1) * (*x); } int main ( ) { int num = 10; square(&num); cout << num; return e; }#include using namespace std3; int main() { int x-6; int y=103; int z=0; int q=1; Z+= X-- -ys q*=++z+y; cout<#include using namespace std; int main() { int x,y; or (x=0 ;x 3) break ; cout << y << endl; | }}} O 5 9. O 4 O 10Functions- Write a C++ function that takes an integer argument, say n, and prints hello n times.C++ Coding: Arrays Given the following code and program output: #include <iostream>using namespace std;double average(const int g[], const int& CAP);void output(const int *g, const int& GRADES, const double& GPA);int main() { const int NUM_GRADES = 5; int grades[NUM_GRADES] = {10, 15, 20, 25, 30}; //average function is called by output function output(grades, NUM_GRADES, average(grades, NUM_GRADES)); return 0;} Example Output: 10, 15, 20, 25, 30GPA: 20 Code function definitions for average() and output(): average() accepts the array and its size as input, and returns the average grade with two decimal places. output() accepts the original array, the array's size, and GPA (generated from the average function) as function parameters. Display the array and GPA.pointers as Arguments:In the C programming language there is no pass-by-reference syntax to passa variable by reference to a function. Instead a variable is passed by pointer(just to be confusing, sometimes passing by pointer is referred to as pass byreference). This Practice Program asks you to do the same thing as C.Here is the header for a function that takes as input a pointer to an integer:1. void addOne (int ∗ptrNum )Complete the function so it adds one to the integer referenced by ptrNum.Write a main function where an integer variable is defined, give it an initialvalue, call addOne, and output the variable. It should be incremented by 1.#180. Run code in C++ compiler #include using namespace std; void fun(int x, int y) { x = 2000; y = 1000; } int main() { X = 100; fun(x, x); cout << x; int x = return e; }This assignment is not graded, I just need to understand how to do it. Please help, thank you! Language: C++ Given: Main.cpp #include #include "Shape.h" using namespace std; void main() { /////// Untouchable Block #1 ////////// Shape* shape; /////// End of Untouchable Block #1 ////////// /////// Untouchable Block #2 ////////// if (shape == nullptr) { cout << "What shape is this?! Good bye!"; return; } cout << "The perimeter of your " << shape->getShapeName() << ": " << shape->getPerimeter() << endl; cout << "The area of your " << shape->getShapeName() << ": " << shape->getArea() << endl; /////// End of Untouchable Block #2 //////////} Shape.cpp string Shape::getShapeName() { switch (mShapeType) { case ShapeType::CIRCLE: return "circle"; case ShapeType::SQUARE: return "square"; case ShapeType::RECTANGLE: return "rectangle"; case…C program only Hi! The 'divide' function should apply recursion. Please fix the code below. #include<stdio.h>#include<stdlib.h> int divide(int, int); int main(void) { int dividend, divisor; printf("Enter the dividend: "); scanf("%d", ÷nd); printf("Enter the divisor: "); scanf("%d", &divisor); printf("%d / %d = %d", dividend, divisor, divide(dividend, divisor)); return 0;} int divide(int dividend, int divisor) { // TODO: Implement this function int S = ((dividend<0)^(divisor<0))?-1:1; dividend = abs(dividend); divisor = abs(divisor); int Q = 0; while (dividend >= divisor) { dividend -= divisor; ++Q; } return Q*S;}c++ computer language what is the output of the following code segment? int main() { int myarray[]={-200, 33, 89, 50, 44}; sub(myarray, 5); for(int i =0; i<5; i++) cout<<myarray[i]<<" "; cout<<endl; system("pause"); return 0; }; void sub(int arr[], int z) { for(int i =0; i<z; i++) arr[i] = arr[i] - i; }SEE MORE QUESTIONSRecommended textbooks for youC++ for Engineers and ScientistsComputer ScienceISBN:9781133187844Author:Bronson, Gary J.Publisher:Course Technology PtrC++ for Engineers and ScientistsComputer ScienceISBN:9781133187844Author:Bronson, Gary J.Publisher:Course Technology Ptr