What is wrong with the following “proof" of the "fact" that n+3 = n+7 for all values of n (besides of course that the thing it is claiming to prove is false)? Proof. Let P(n) be the statement that n + 3 = n + 7. We will prove that P(n) is true for all n e N. Assume, for induction that P(k) is true. That is, k + 3 = k + 7. We must show that P(k + 1) is true. Now since k +3 = k + 7, add 1 to both sides. This gives k + 3 +1 = k + 7 + 1. %3D

College Algebra (MindTap Course List)
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Author:R. David Gustafson, Jeff Hughes
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Chapter8: Sequences, Series, And Probability
Section8.5: Mathematical Induction
Problem 42E
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What is wrong with the following "proof" of the "fact" that n+3 = n+7
for all values of n (besides of course that the thing it is claiming to
prove is false)?
Proof. Let P(n) be the statement that n + 3 = n +7. We will prove
that P(n) is true for all n e N. Assume, for induction that P(k) is true.
That is, k + 3 = k + 7. We must show that P(k + 1) is true. Now since
k + 3 = k + 7, add 1 to both sides. This gives k + 3 + 1 = k + 7 + 1.
Regrouping (k +1)+3 = (k+1) +7. But this is simply P(k+1). Thus by
the principle of mathematical induction P(n) is true for all n e N. QED
Transcribed Image Text:What is wrong with the following "proof" of the "fact" that n+3 = n+7 for all values of n (besides of course that the thing it is claiming to prove is false)? Proof. Let P(n) be the statement that n + 3 = n +7. We will prove that P(n) is true for all n e N. Assume, for induction that P(k) is true. That is, k + 3 = k + 7. We must show that P(k + 1) is true. Now since k + 3 = k + 7, add 1 to both sides. This gives k + 3 + 1 = k + 7 + 1. Regrouping (k +1)+3 = (k+1) +7. But this is simply P(k+1). Thus by the principle of mathematical induction P(n) is true for all n e N. QED
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