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- Content C °- OWLv2 | O × Google Do G google slid x Inbox (4,5 x Certificate ☑ > Course E X Cengage L ✓ b Calculate ✓ ChatGPT × + prod03-cnow-owl.cengagenow.com/ilrn/takeAssignment/takeCovalentActivity.do?locator-assignment-take E4 CH 16 17 and 18 [References] Question 1 1 pt This question has multiple parts. Work all the parts to get the most points. Question 2 2 pts Question 3 1 pt Question 4 2 pts Trimethylamine, (CH3)3 N, is a common reagent. It interacts readily with diborane gas, B2H6. The latter dissociates to BH3, and this forms a complex with the amine, (CH3)3 N→BH3. The reaction between trimethylamine and borane is shown. Question 5 1 pt Question 6 × 2 pts Question 7 1 pt CH3 H CH3-N: + B CH3 H CH3 H CH3 -N- CH3 H Question 8 2 pts Is the BH3 fragment a Lewis acid or a Lewis base? To decide this, answer the following questions: Question 9 1 pt Question 10 2 pts a Which of the following is a definition of a Lewis acid? Question 11 1 pt Question 12 1 pt proton donor electron pair…Ca(QCI)2 + 2 CH3COOH E-> 2HOCI + (CH3COO)2Ca|enow.com/ilrn/takeAssignment/takeCovalentActivity.do?locator-assignment-take ist: anxiet... E COVID-19 and Nig... ▪▪▪ Coronavirus: A vis... Preq Ereg req req req C $ 4 8 In the illustration: The product that forms is The limiting reagent is The number of C The number of product molecules formed is % 5 Corona virus: Cos... MP People who rely o... G covid 19 and the e... [Review Topics] [References] Use the References to access important values if needed for this question. G Search or type URL 1 The illustration to the left represents a mixture of hydrogen (light blue ) and iodine (purple) reacting to form a product. 6 Cengage Learning Cengage Technical Support atoms/molecules in excess is & 7 ☆ * 8 X ( 9 < 0 C Ho
- Cengage Learnir × | Cengage Learnir x | Cengage Learnir X OWLv2 | Online X × Ar Ex3 CH 14 and 15 prod03-cnow-owl.cengagenow.com/ilrn/takeAssignment/takeCovalentActivity.do?lo Question 1 1pt This question has multiple parts. Work all the parts to get the most points. Question 2 1pt Question 3 Question 4 2 pts 2 pts Data in the table were collected at 540 K for the following reaction: Question 5 1 pt CO(g) + NO2(g) → CO2 (g) + NO(g) Initial concentration (mol/L) Initial rate Question 6 Question 7 2 pts 1pt [CO] [NO2] (mol/L. h) 5.1 × 10-4 Question 8 Question 9 2 pts 1pt Question 102 pts Question 111pt 0.35 x 10 4 3.9 × 10-8 5.1 x 10-4 0.70 × 10-4 7.9 x 10-8 5.1 × 10-4 0.18 × 10-4 2.0 × 10-8 1.0 × 10-³ 0.35 × 10-4 7.7 × 10-8 Question 12 1 pt 1.5 x 10-3 0.35 × 10-4 1.2 × 10-7 Question 13 1 pt Question 14 1pt Question 151 pt a Determine the reaction order with respect to each reactant. Order with respect to CO: 1 ✓ ✓ 4 Order with respect to NO2: 1 V✓ Progress: 13/15 items Due Mar 28 at…M myMCC | Middlesex College x e Chapter 6 * OWLV2 | Online teaching and X b Answered: A 2.00 g sample o x h Hulu | Watch f → C A A https://east.cengagenow.com/ilrn/takeAssignment/takeCovalentActivity.do?locator=assignment-take G R Tp Apps P Pin FB M Matwa MCCMai Pay -zu:brar I Vitaurce Booksh. e SelfServ M myMCC b b M mail E Reading list P pay Other bookmarks >> Chapter 7 [References] Microwaves have frequencies in the range of 10° to 1012 /s (cycles per second), equivalent to between 1 gigahertz and 1 terahertz. What is the wavelength of microwave radiation whose frequency is 3.780 x 1010 /s? The speed of light is 2.998 × 10° m/s. Question 4 1 pt Question 5 O 1 pt Wavelength = m Question 6 O 1 pt Question 7 1 pt Submit Answer Try Another Version 6 item attempts remaining Question 8 O 1 pt Question 9 O 1 pt Question 10 1 pt Question 11 1 pt Visited Question 12 O 1 pt Question 13 1 pt Question 14 O 1 pt Question 15 1 pt Question 16 1 pt Question 17 O 1 pt Question 18 1 pt Question 19 1…em1.png chem3.png Part 3: Q9 Average absorbance Flask 8 Flask 9 Flask 10 Flask 11 Part 3: Q9 Flask 8 Flask 9 Flask 10 Flask 11 Part 3: Q10 Flask 8 Flask 9 Flask 10 Flask 11 Q Part 3 0.146 [Fe] -0.002mol/L 0.166 volume 5.00mL 0.215 0.294 [FESCN mol/L) ✪ 4.59* 10 5.18*10* 6.64 x 10 9.08*10* [Fe(mol/L) 5.00 x 10 5.00*10* Y=3362x -0.0083 R¹ 0.9993 5.00 x 10 5.00*10* (Amounts of flask 8 (9 - 11's values are in the spreadsheet) 1:1 Ratio so, Molarity of Fe(NO3))3 = 0.2M Volume of Fe(NO3))3 = 5.00mL 71% Moles of Fe³= Molarity x volume(L) Moles of Fe = 0.2M × 0.005L = 1× 10-³mole 68% [SCN ](mol/ 4 x 10-4 5 x 10-4 7*10* 1*10* الخا chem2.png Concentration of Fe³ 9, X = mole of Fe³1x10³ mole Volume 0.0054 Ⓒ 8, Average absorbance for solution 8 (same for 9 - 11) Average absorbance for flask 8 = sum of all absorbances / number of readings (0.145 +0.147 +0.148) 3 Using equation of calibration curve's line(slope) of best fit, the average absorbances of the unknown concentrations to determine…
- Document1 - Word Search (Alt+Q) References Mailings Review View Help Write the corresponding letters to the following descriptions. Each proposal can be associated with 0 or 1 match and each letter is not necessarily associated with a proposal. a. [Ar] 4s? b. 1s 2s2p63s23p3 c. 1s2s2p2 d. [Ne] 3s23ps e. [Ar] 4s23d10 f. 1s22s! g. None of those answers 1. I am a halogen 2. I am a transition metal 3. I am alkaline 4. I have exactly 2 single electrons 5. I am the smallest of the atoms presented here 6. I have exactly 3 valence electrons 7.I am the most paramagnetic of the atoms presented here 8. I am the copper 9.I am isoelectronic with Ti2+ IF cessibility: Good to go IA 16 SIS27. Complete las siguientes reacciones: Br -OH а. b. + -OCH3 -OCH,CH3 С. the Br + OCH,on O C The u receptors are a class of opioid receptors. The binding affinity of several compounds is shown below: Compound Binding affinity 2.55 nM || ||| IV 33.6 nM 156 nM 600 nM H i. Which compound has the weakest binding to the μ receptor? Justify your answer. ii. Which compound has the strongest binding to the μ receptor? Justify your answer. DJelsim Suppost 2² Tina, me 3 Course Hero' Rewards 2 OSHC Claims (Allian. 7 warded messa N Telsim Prepaid Pack [04933442 invoice and referral - Good morni Good news: you have new rewards o + bly Re-Further information Regi 8 Google recommends Chrome 24℃ 대체로 화창 A 9. 2023
- is polar or nonpolar. Do not draw double bonds to oxygen atoms unless they are needed for the central atom to obey the octet rule. Do not include formal charges in your drawing. XeO3 polar nonpolar 826RRA 000-F 12Q)A histidine solution with a concentration of C = 60.5 mg/L has an absorbance of 0.794 when the light path length is 1.0 cm. Note that the molecular mass of tryptophan is 155.15 g/mol. 1-Calculate the molar absorbance of a histidine solution expressed as L.mol 1.cm-1. 2-Description of the preparation of 100 mL of a 15.0 ppm histidine solution mentioned above(17360 Systane Part B CH3 CH3 CH3-CH₂-CH-CH-CH₂-OH Spell out the full name of the compound. Submit Request Answer Part C OH CH₂-CH3 P dy 44#1 BAKER -2221 51-19-145 ciation, Inc. OS WINE 19 25 OCT 2022 PM) Address Herbert Epstein 14773 Cumberland C DELRAY BEACH, F အင်းတင်း 46-135654 2 ^ [