The RDT 3.0 protocol. As we learned in class, the rdt3.0 protocol reliably transfers data from sender to receiver over achannel that can corrupt, lose and delay (but not reorder) packets. The rdt 3.0 sender and receivers (taken verbatimfrom the texbook and frmo our class notes) are shown below FYI. Recall that the sender starts in state "Wait for call 0from above", and the recceiver starts in state "Wait for O from below".rdt_rcv(rcvpkt)Ardt_rcv(rcvpkt)&& notcorrupt(rcvpkt)&& isACK(rcvpkt,1)stop_timertimeoutudt_send(sndpkt)start_timerrdt_rev (revpkt) &&(corrupt (revpkt)||has_seq1 (revpkt))sndpkt-make_pkt(ACK, 1, checksum)udt_send (sndpkt)rdt_rcv(rcvpkt) &&(corrupt(rcvpkt) ||isACK(rcvpkt,0))Asend packetreceive ACKsend packetsendertimeoutsend packetreceive ACKsend packet t602O O0 1Wait forcall 0 fromaboverdt_send(data)rdt_rcv(rcvpkt) &&sndpkt make_pkt(0, data, checksum) (corrupt(rcvpkt) ||udt_send(sndpkt)isACK(rcvpkt, 1))Astart_timerWaitforACK1rdt3.0 senderextract (revpkt, data)deliver_data (data)sndpkt-make_pkt (ACK, 0, checksum)udt_send(sndpkt)rdt_rev (revpkt) && notcorrupt (revpkt)&&has_seq0 (revpkt)Wait for RDT 3.00 frombelow receiverlossrdt_send(data)sndpkt make_pkt(1, data, checksum)udt_send(sndpkt)start_timerextract (revpkt, data)deliver_data (data)sndpkt-make_pkt (ACK,1, checksum)udt_send(sndpkt)rdt_rev (revpkt) && notcorrupt (revpkt)& & has_seql (revpkt)Now consider the diagram below showing the operating of the rdt3.0 protocol. In this diagram, we have intentionallyleft out the sequence numbers and ACK numbers in the packets sent by rdt3.0 (that's what we'll ask about in thisquestion).receiverWaitforACKOreceive packet¹¹send ACKt3receive packetsend ACKWait for1 frombelowreceive packetsend ACKWait forcall 1 fromaboveO There is no sequence number used on this packet.timeoutrdt_rcv(rcvpkt)udt_send(sndpkt)start_timer&& notcorrupt(rcvpkt)&& isACK(rcvpkt,0)stop_timerrdt_rcv(rcvpkt)AWhat is the sequence number on the packet sent by the sender at time t₂? (Note: there is only one correct answerbelow).rdt_rev (revpkt) &&(corrupt (revpkt) ||has_seq0(revpkt))sndpkt-make_pkt (ACK, 0,checksum)udt_send(sndpkt)

This is very simple. The correct answer is option c) which is 1 Explanation…

Answered: What is the sequence number on the…

What is the sequence number on the packet sent by the sender at time t₂? (Note: there is only one correct answer below).

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Please solve it correctly and please provide explanation of your answers. A PC and a Web Server are communicating over a TCP connection. The PC had started the three way handshake with the initial sequence number of 3069 . The Web Server's initial sequence number is 4830 . The window size of the PC is 815 bytes and the window size of the Web Server is 463 bytes. Using the third TCP handshake ack segment the PC sends the http request of the size 396 bytes to the Web Server. Then the Web Server answers with 3 segments containing the requested data. The first segment size is 42 bytes and the second segment size is 276 bytes and the third segment size is 146 bytes respectively. The PC receives all three segments within the timer. But unfortunately the second segment was corrupted. So the PC immediately sends an acknowledgement segment. Assume that the PC uses Selective Repeat/Reject ARQ. (a) What will be the sequence number of the third TCP handshake signal send from PC to webserver?…
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