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- 2) 1. Februurg 2, 2022 Lyonel Tanis CHM-0IL Section: C16130) Name: Date: Report Sheet: Characterization of a Weak Acid. UNKNOWN NUMBER A. Standardization of NaOH Solution TRIAL [HCI] Volume Moles Moles Volume [NAOH] HCI NaOH NaOH 24.65 25.75 0.1002 25.89 25.73 Average [NaOH]. B. Identification of the Unknown Acid 8. Determination of Molecular Weight TRIAL [NaOH] Volume Moles Moles Grams Molecula Unknown HOBN Unknown r Weight (g/mol) NaOH 0.2947 Lohe 24.07 1. 0.2943 2. 3 Average Molecular Weight (g/mol)3 How to Titrate: Lab Techniques Titration Titration Procedures: Add about 100mL of a 0.1 M NAOH solution to a 250mL beaker. 2. Obtain a buret and rinse with about 10 ml of the NaOH solution. 3. Fill the buret with NaOH and record starting volume to the nearest 1m" of a milliliter. 4. Measure out exactly 10.0 ml of HC in a graduated cylinder and add it to a 250mL Erlenmeyer flask along with 1 drop of phenolphthalein indicator. 5. Slowly add the NaOH to the flask with the acid and swirl. Continue adding the base until a color change (faint pink) occurs and remains for at least 10 seconds. This is the endpoint of this neutralization eaction. 6. Read and record the ending volume of NaOH in the buret, 7. Repeat steps 1 through 6 two more times for Trials 2 and 3. 8. Calculate the volume of base added in each trial. 9. Use the volume of base added and the volume of acid added to calculate the molarity of the acid for each trial. 10. Calculate the average molarity of the acid. 11. Calculate…Give correct solution..don't give Handwritten answer
- Xanthurenic acid stock solution Absorbance 25 0.052 50 0.128 75 0.202 100 0.310 150 0.448 200 0.621 Plot a graph, from graph, y=mx (force the trend line to pass through origin since the blank with no xanthurenic acid was set to be zero absorbance) in which, y: Absorbance, x concentrationPlease help with atleast 3qs as per guidelines. Need correct solution.a. What is the percent ionization in 0.80 M NH3 (Kb Percent ionization = % % = % 1.8 × 10-5)? b. What is the percent ionization in 0.090 M NH3 (Kb Percent ionization = c. What is the percent ionization in 1.0 M CH3NH₂ (Kb = 4.38 × 10¯4)? Percent ionization = = 1.8 × 10-5)?
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