What is the maximum number of bytes that can be included in a UDP payload?
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What is the maximum number of bytes that can be included in a UDP payload? (Hint: the answer to this question can be determined by your answer to 2. above)
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- ASN.1 is an ISO standard used in many internet‑related protocols, especially those in the area of network management. In ASN.1, BER (Basic Encoding Rule) uses a so‑called TLV (Type, Length, Value) approach to encoding data for transmission. According to this BER encoding rule, what would be the encoding of {weight, 178} {lastname, “Philips”}?USING JAVA (Java Socket /TCP Programming) Create a chat/messaging application that has the following functionalities/features: Broadcast message (to all users) Private message to only one message (established usernames are stored in an XML file)9.Correct expression tor UDP user datagram length is length of UDP = length of IP- length of IP header's length of UDP= length of UDP-length of UDP header's length of UDP = length of IP+length of IP header's length of UDP = length of UDP+length of UDP header's.
- In IPv4, the address format is a 32-bit numeric number that is frequently written as four octets separated by periods from the range [0, 255]. At the time of writing, Internet Protocol version 6 (IPv6), with 128-bit addresses, was gradually replacing IPv4. How many IP addresses may be assigned in IPv4 and IPv6 in theory?IKT204-G H21, Routing tables 13 In this assignment, the objective is to determine the correct forwarding link given the routing table below. A router has the following entries in its forwarding table: Link1: 00001010.10101000.00000100.00000000/22 Link2: 00001010.10101000.00000110.00000000/23 Link3: 00001010.10101000.00000111.00000000/24 Link4: 00001010.10101000.00000000.00000000/16 Link5: All other addresses Assume the router receives IPV4 datagrams destined to the following addresses and decide which link they are forwarded to: A: 00001010.11111000.00000101.00001111 B: 00001010.10101000.00000111.00011000 C: 00001010.10101000.00000011.01010000 D: 00001010.10101000.00000111.11111110 E: 00001010.10101000.00000110.10000010 On which link will they be forwarded? A: link B: link C: link D: link E: linkWhat two of the following arguments are strongest in support of layered protocols?
- We have seen that Internet TCP sockets treat the data being sent as a byte stream but UDP sockets recognize message boundaries. What are one advantage and one disadvantage of byte-oriented API versus having the API explicitly recognize and preserve application-defined message boundaries?For NAT Network Address Translation Scenario: Jenny Bello is a small business owner selling and making customized computer peripherals. She has been finding it difficult to track her sales and inventories, however recently after an expert's advice, she adopted a Point of Sale (PoS) server. So, she can now track her sales and inventories at the store. However, she ran into another issue, the server can only be accessed within the store, because it has been assigned a private IPv4 address, it is not publicly accessible via the Internet. a) Why is not having the PoS server accessible over the Internet a problem for the business? b) What caused this problem? c) Propose a solution for the problem and explain how the solution works.Explain the sentence “Lower layer protocols encapsulate higher-layer data”
- TCP is one of the most common protocols operating at the transport layer and providing reliable end to end devlivery. TCP header is a variable length header since it might contain OPTIONS field. Write a report explaining the different options that can be added in this field.We have seen that Internet TCP sockets treat the data being sent as a byte stream but UDP sockets recognize message boundaries. What are one advantage and one disadvantage of byte oriented API versus having the API explicitly recognize and preserve application-defined message boundaries?assume that the link layer uses the flag bytes with byte stuffing approach for framing, with the following details: The beginning of a data frame is indicated by the special flag bytes: DLESTX The end of a data frame is indicated by the special flag bytes: DLEETX The special escape bytes DLE are used for escaping accidental occurrences of either the flag bytes or the escape bytes within the data. For simplicity, assume that no other header/trailer information is added to the data. 1. The following byte stream represents data that needs to be framed by the link layer on the sender’s side. Derive the resultant byte stream by adding necessary flag bytes and performing byte stuffing. ASTXDLELEFTDAOY I have this answer but it is wrong DLESTXASTXDLEDLELEFTDAODLEETX