What is ∆H (in kJ/mol) for a reaction where the activation energy is 250 kJ/mol while the activation energy for the reverse reaction is 150.0 kJ/mol

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Chapter18: Chemical Equilibrium
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What is ∆H (in kJ/mol) for a reaction where the activation energy is 250 kJ/mol while the activation energy for the reverse reaction is 150.0 kJ/mol?

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Formula of activation energy

Ea1= ∆H + Ea2

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