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What are the skeleton equations for these reactions?
Ca+Mg(NO3)2-->
Ca3P2+H2SO4-->
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- Consider the equation G = -nF. What are the four terms in this equation? Why does a minus sign appear in the equation? What does the superscript o indicate?When jump-starting a car with a dead battery, the ground jumper should be attached to a remote part of the engine block. Why?Iron (II) can be oxidized to iron (III) by dichromate ion, which is reduced to chromium (III) in acid solution. A 2.5000-g sample of iron ore is dissolved and the iron converted into iron(II). Exactly 19.17? ml. of 0.0100 M Na2Cr2O7 is required in the titration. What percentage of the ore sample was iron?
- Consider the reaction: H;C,O, + KMNO, + H,SO, CO, + MnSO, + K;SO, + H,O. What should be the coefficient of H;C,O, in order to balance the equation?The mercury in a 1.0287-g sample was precipitated with an excess of paraperiodic acid, HglOg 5Hg* + 2H,IO, → Hg,(IO,); + 10H* The precipitate was filtered, washed free of precipitating agent, dried, and weighed, and 0.4788 g was recovered. Calculate the percentage of Hg;Cl2 in the sample. *only the value must be writtenA sample containing NaCl, NaBr, & inert material weighs 1.000 g. Excess of AgNO3 gave a whiteprecipitate consisting of only AgCl and AgBr which weighs 0.5260 g. By heating the precipitate in a currentof Cl2 gas, the AgBr (187.78 g/mol) is converted to AgCl (143.32 g/mol) and the precipitate weighs 0.4260g. Find the % NaCl (58.44 g/mol) and % NaBr (102.909 mol) in the original sample.
- A 1.500 g sample of an aluminum is dissolved and the sulfate is precipitated as BaSO4-. The precipitate weighed 0.3486 g after it was washed and ignited. Assuming all the sulfate and aluminum in the sample were in the form of K2Al2(SO4)3 24 H20. Calculate the percentage of Al2O3 in the sample. Express the answer in 3 SF. Input only the value.A o.8024 g sample of an iron ore is dissolved in acid. The iron is then reduced to Fe and titrated with 46.21 mL of 0.02238 M KMNO4, solution. Below is the analytical reaction. MnOa- + 5Fe2+ +8H+ - Mn2+ + 5FE3+ + 4H20 Calculate the result of this analysis interms of % Fe (Molar Mass = 55.845 g/mol).coulbonug9 oinihe olni bouogmoOB QU llaa of word Solubility Rules: Water Soluble Compounds EXSube sCHcood) or etosiq 1. Salts of ammonium (NH4*) and Group IA are always soluble. 2. Salts containing nitrate (N03-), acetate (C2H3O2-), or chlorate (CIO3-) ions are always soluble. enoiteo 1ol ooJ 3. Salts of the halides are soluble with the following exception: a. Compound containing Ag*, Hg2*, Pb²* prirdolaw Jon er Es i olnol the exception of: 4. Salts containing the sulfate ion (SO42-) are soluble elgmsx3 a. Compounds containing Ag*, Hg2*, Pb²+, Ca2*, Sr2*, or Ba2+ Water Insoluble Compounds Juloe ent! 1. Salts of the carbonate (CO32-), phosphate (PO43-), chromate (CrO42-), or sulfides (S2-) ions are insoluble with the exception of compound containing group 1A or ammonium cations. 2. Salts containing the hydroxide ion (OH-) are insoluble with the exception of compounds containing group 1A, ammonium cations, or Ba2+. biup Inot luo tneioliteoo belon Soluble means that it dissolves in water…
- Molecular equation: CaSO; (s) + 2HI(aq) → Cal, (aq) + SO, (9) +H;O(1) b write corresponding net lonic equation. CaSO; (s) + HI(ag) → (Use the lowest possible coefficients. Be sure to specity states such as (aq) or (s). If a box is not needed, leave It blank. Use H* for hydronium fon.) + +1) Predict the balanced ionic formula for calcium citrate: 2) Balance the precipitation reaction below: Ca(CH;COO)2(aq) _Ca3(CcHsO;)2(s) +_Na*(aq) + Na3C¢H3O7(aq) CH;COO-(aq) + - ↑Ores are analyzed by dissolving some of the ore and then performing an analysis of a metal (expressed in grams); usually the concentration of the metal is expressed as % of the amount of the ore (in grams) dissolved. An ore containing Sn was dissolved and then titrated with MnO4-. When 14.1960 g was dissolved and titrated with 0.1535 M MnO4- the titration required 35.32 mL to reach the endpoint. What was the % Sn in the ore?5Sn2+(aq) + 2MnO4-(aq) + 16H+(aq) ↔ 5Sn4+(aq) + 2Mn2+(aq) + 8H2O(l) 18.14%