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- 2. Below are drawn four possible isomers (partial Lewis structures with different atomic connectivity) for an anion with the molecular formula C3H4NO¯. A B HC N D H H H FO C H H H H H H H -H "SIT H H H C-C-H HIC= I H H-C= H -2 <-<=Ö: 1 I H H VIH - C 11 71 =0-c-c-H ( H HSee Figure 2-4. The MOST correct line drawing for the molecule shown is A B UWhich one is the correct representation of methane (CH4) in 3 D shape (using wedge-dash line model)? Η Η Η Η Ή H"Η Τ Οι ΟΙ Ο III ΟIV Η Η || -H III
- See Figure 2-3. Do an orbital analysis of C-2 (arrows on lines like we did in class). It has a pi bond to C-1 and a pi bond to C-3. What is its hybridization? sp3 sp2 spConvert the following line-bond structures into molecular formulas: (a) CH₂OH H H H H کی C= = с с C )-1 H (c) H、 N. с (=^ 0=C с FO Aspirin (acetylsalicylic acid) 0 )=0 с C C=0 OH H C || H CH3 ć с N Nicotine C 1 с с H HY C-C T H H CH3 )—I C H I I H (b) (d) HO H 4-C I HO HO H H₂ H-C C=0 Vitamin C (ascorbic acid) C=C CH₂OH C-O C C-C HO но| | H H OH OH Glucose H OH 11OH O || CH,CHC-CH, Identify the appropriate bond(s) by selecting each atom individually on the canvas and assigning them a map number of 1 until all atoms of the bond are mapped. DQ ⓇH: 2N CONT NN 1. (1) A" ΔΕ OH O H₂C-C-C-CH₂ O O 0 Od H C N O S CI Br I P F
- MgBr Mg C,H,OC,H, MgBr o-CH O *MgBr C,H,OC,H, + CH,OH H,O, H,SO, O "MgBr OH Data Glassware oven-dried, assembled, placed under nitrogen (balloon). Materials: 10 mL anhydrous diethyl ether, 1.0 g Mg turnings. 4.5 mL bromobenzene. 10 mL more anhydrous diethyl ether. 2.5 ml methyl benzoate. Approximate initiation time: 15 min. Stir 10 min after addition of methyl benzoate. Transfer reaction mixture to 100 mL Erlenmeyer flask. Rinse reaction flask (2 x 20 mL diethyl ether). Acid quench solution: 25 mL 10 % aqueous sulfuric acid/15 g ice. Saturated NaCI solution: used 20 mL Hexanes: 20 mL Isolated: 1.82 g white solid What is the % yield of the reaction? What is the limiting reagent? Show complete calculations for the theoretical and % yield calculationsDraw a Bond-Line Structure for the following Compound H—O: H | | H H-C-C-O-C-C=C-C HICIH H I | I I. H H H H H HH H C H C 1 1 H-C-C-C-C-C-H →>> III ннс H H H-C-H H H HIC H H C-C-Hd. C,H, + 50, -> 3Cо, + 4H,0 ö=ö ö-ö ö=ö ö-Ö ö=c=Ö ö=C=Ö Ö=C=ö H-C-C-C-H J. J. J.