We are standing on the top of a 384 feet tall building and launch a small object upward. The object's vertical position, measured in feet, after t seconds is h(t) 16t² + 32t + 384. What is the highest point that the object reaches? = - feet

We are standing on the top of a 384 feet tall building and launch a small object upward. The object's vertical position, measured in feet, after t seconds is h(t) 16t² + 32t + 384. What is the highest point that the object reaches? = - feet

Elementary Algebra

17th Edition

ISBN:9780998625713

Author:Lynn Marecek, MaryAnne Anthony-Smith

Publisher:Lynn Marecek, MaryAnne Anthony-Smith

Chapter10: Quadratic Equations

Section10.4: Solve Applications Modeled By Quadratic Equations

Problem 10.84TI: A man throws a ball into the air with a velocity of 96 ft/sec. Use the formula h=16t2+v0t to...

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Question

We are standing on the top of a 384 feet tall building and launch a small object upward. The object's
vertical position, measured in feet, after t seconds is h(t) — 16t² + 32t + 384. What is the highest
=
point that the object reaches?
feet

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