Venus can be as bright as apparent magnitude -4.7 when at a distance of about 1 AU. How many times fainter would Venus look from a distance of 6 pc? Assume Venus has the same illumination phase from your new vantage point. (Hints: Recall the inverse square law; also, review the definition of apparent visual magnitudes. Note: 1 pc = 2.1 x 105 AU). |times fainter What would its apparent magnitude be?
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There are two parts to this question. I need to know how many times fainter Venus is from a distance of 6 pc and what the apparent magnitude would be as well! Thank you!!
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