HOW DID HE GET THE VALUE INSIDE THE CIRCLE cos² x D²+1 For given particular integral multiplying and dividing by 2 will give us 1/ { 2 cos² Xx Ур Yp = = D²+1 S now using trigonometric identity 2 cos²x = 1 + cos 2x we have Ур = Ур 1/{ {{ Xp = = = { ².1 + D²+cos 2x} D+1 1+cos 2x D²+1 1 Yp = = { 0 + 1 + = 4+₁ cos 2x} Ур 0+1 -4+1 = cos 2x 3 Yp = 1/2 = cos 2x Ур 6

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