Match the components of bacterial replication and transcription correctly.v [Choose ]Topoisomerase Ilhelicase loaderRNA polymerasemust accumulate enough for DNA replication to beginSingle stranded binding proteinsigma factorproteins of the RNA polymeraseadds nucleotides to RNA transcriptDnaAbacterial helicaseDNA gyrase -needed for recognition of promoter site in transcriptionBeta clampDNA polymeraseTau complextwo alpha units, beta, beta prime, and omegaDnac[ Choose )DnaB( Choose]

In transcription process RNA polymerase play major role which is a holoenzyme consist of core enzyme…

V [Choose ) Topoisomerase II RNA polymerase helicase loader must accumulate enough for DNA replication to begin Single stranded binding protein proteins of the RNA polymerase adds nucleotides to RNA transcript bacterial helicase DNA gyrase - needed for recognition of promoter site in transcription Beta clamp DNA polymerase Tau complex sigma factor DnaA two alpha units, beta, beta prime, and omega Dnac [Choose ) DnaB (Choose ]

V [Choose ) Topoisomerase II RNA polymerase helicase loader must accumulate enough for DNA replication to begin Single stranded binding protein proteins of the RNA polymerase adds nucleotides to RNA transcript bacterial helicase DNA gyrase - needed for recognition of promoter site in transcription Beta clamp DNA polymerase Tau complex sigma factor DnaA two alpha units, beta, beta prime, and omega Dnac [Choose ) DnaB (Choose ]

Biology: The Unity and Diversity of Life (MindTap Course List)

14th Edition

ISBN:9781305073951

Author:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Publisher:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Chapter9: From Dna To Protein

Section: Chapter Questions

Problem 15SQ: Match the terms with the best description. __ genetic message a. protein-coding segment __ promoter...

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pcc300ATAAADATATAOOTTAA 1. Use the genetic code table and the information in the diagram below to determine the amino acids that would make up the portion of the polypeptide shown. Include information for a key as well. DNA template 3' G CATA ACAGAGGATT-5' al bnsua AMAm pniwollot erfT E transcription s yd bnsita ebitgeqylog s sidmeaze of beae RNA strandUU UAOUOUU A-emoaodin 5'-CGUA AUUGUC UCCUUA- 3' J J JL erit o elinW (s) translation bluow terdt aspnso sigootiwsone polypeptide viemetis ns ebivo19 (d) ent ot etslanT Key:
E D ot OH ON O Replication R SORO Transcription ORNA processing Translation Gene expression 657 F Q Search % T G LOCLE Y F7 & 87 F8 U 99+ 8 F9 53879 10 F10 O 2 H J K L CV BN MO < F12
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Coding DNA 5’- GTG ACT CGT TGT GCC ATT GCA GCT AAA CAC TTC GAG CCC TGT- 3’ mRNA 5’- GUG ACU CGU UGU GCC AUU GCA GCU AAA CAC UUC GAG CCC UGU- 3’ What is the polypeptide sequence?
LIAINAS SA4) Fill in the missing DNA, MRNA, anticodon and protein sequence. A codon table is available at the end of the exam. Make the anticodon complementary Template strand 3' T_A G _C 5' Non Template 5' ACA -- 3' MRNA 5' 3" Anticodon 3' 5' Protein Thr Arg in in
E The arrow in the diagram below indicates the direction of transcription. BTTL c. A ATGCCGCA AUGCCCCAAUCUG TACGGCGTTAGAC OA OB с Q Search Which letter indicates the 5' end of the DNA template strand? R F TTCACGCACTCATSTOFACCACGTA T G Direction of synthesis- CG STACATGAGIAC LOC Y H Krit & 7 FO U 99+ * 8 D ATEGTGCAT CVBNM MO DE 79 Alt F:-10 KL E 0 P ^ @ ¹ F12 Ctrl 10:37 AM 4/8/2023 10
nd 2 minutes): Any RNA polymerase in any organism: O A Synthesizes RNA chains in the 3 to-5" direction O B. Binds tightly to a reqion of DNA located thousands of base pairs away from the transcobed rogion of the DNA OC Has proofreading activity O D. Separates DNA strands throughout a long region of DNA (up to tinousands of base pairs) and then copies one of them. OE Has a subunit called A (lambda), which acts as a proofreading ribonuclease OF. Can initiate synthesis of a new RNA chain without a primer
vvnicn the following statements are correct about the repair of a DNA duplex containing the sequence below that is grown INE coli (select all that apply)? Strand A Strand B GATCTAGCCGGCATCCGAT CTAGATCGGACGTAGGCTA Methyl ✔A. MutH cleaves Strand A O B. DNA repair will result in the bold A in strand B being replaced with a C O C. DNA repair will result in the bold G in strand A being replaced with a T ✔ D. Defect will not be properly repaired in dam(-) E coli O E. The mammalian repair system would also correct the mismatch shown based on the methylation status of the DNA
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Match the terms with the best description. __ genetic message a. protein-coding segment __ promoter b. KN A polymerase binding site __ polysome c. read as base triplets __ exon d. removed before translation __ genetic code e. occurs only in groups __ intron f. complete set of 64 codons