V₁ = 24 m/s 0=35°
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A football player throws the ball with the initial conditions as shown in the figure. Calculate the radius of curvature and the rate of change of velocity dv/dt at t=1s and t=2s. t=0 is the moment the ball leaves the player's hand.
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- Q2 The man stands 18 m from the wall and throws a ball at it with the speed of 15 m/s as shown in Figure Q2. He release the ball at an angle of 0 = 30° so that it strikes point B at the height of h1. The ball reached the maximum height at C. (a) Find the component of velocity in x-direction just before it hit the wall at point B. (b) Caleulate the time of flight of the ball from A to B. (c) Determine the height of h1 when the ball reach and hit the wall at point B.The sprinter begins from rest at position A and accelerates along the track. If the stationary tracking camera at O is rotating counterclockwise at the rate of 12.8 deg/s when the sprinter passes the 61-m mark, determine the speed v of the sprinter and the value of r. 42 m O 12 mFind hught P⋅E= 33.355 m = 3kg g=10m/s2
- Q1: 1. 3. Find the relative velocity of car A relative to в. Choose the correct answer 20 m/s 50 m/s A car is moving on a concave road as shown [30 m/s Find the reaction between the car and road mass of car = 900 kg and R = 50 m ( assume g = 10 m/s ) ( a =v/r) Select one: Select one: a. 50 m/s angle 45 a. 18000 kg b. 58.3 angle 30.9 b. 1800 kg c. 50 m/s angle 36.87 c. 18000 N d. 40 m/s angle 30 d. 16200 N 2. 4. A car initial velocity is 12 m/s moves with accn 3 Find the accn of the frictionless system shown. m/s Assume the pulleys are light and have no friction Assume g = 10 m/s" Find the its velocity after it moves a distance of 4kg 120 m 8 kg { laws you may use are 2 V,- V, = at , v. - v, = 2zas , s = v, t• 0.5 at } D1kg 5 kg Choose the correct answer Select one: a. 29.4 m/s Select one: b. 29.4 mm a. 1.579 m/s c. 23 m/s b. 2.22 m/s d. 21.9 m/s C. 2 m/s O d. 3 m/sNote: In the text, all questions use 62.5 pounds/ft as the force per volume density of water. In metric, we would need Newtons/meter. The mass density per volume of water is 1000 kg/m³. To convert this into a force density per volume, we multiply by gravity, approximately 9.8 m/s?. The resulting quantity is the force density per volume in metric: 9800 N/m³.Given: Va and 0 Find: Horizontal distance it XB travels and vc- B VA = 10 m/s Plan: Apply the kinematic relations in x- and y- 30° directions.
- You are being asked to determine the heights in tubes B and C (relative to z=0) given the following information: The specific weight of Air is Pair = 11.9N/m3 The specific weight of glycerine is Paiye = 12355N/m3 The specific weight of gasoline is Pgas = 6677N/m3 The gauge pressure at A is Pa = 1.6kPa The height of the tank of air is a = 1.7m The height of the tank of gasoline is y = 1.6m The height of the tank of glyercin is k = 0.95m A в с xm Air y m Gasoline k m Glycerin z = 0 As a HINT, you do not need to know the specific elevations of the tubes B and C entering their respective fluids, but you do need to account for this. Input the height the fluid rises in B to 2 decimal places here: (in metres) Input the height the fluid rises in C to 2 decimal places here: (in metres)The pressure in a water tower is 20,674 Pascals (N/m2) higher than at an open faucet. The density of water is 1000 Kg/m3. Use Bernoulli’s equation to determine the velocity of outflow from the open faucet. If the height difference between the top water level in the tower and the faucet is 7.2 meters, then the velocity of outflow is ROUND TO 3 DECIMAL PLACESF = (128)(s+1)N (to right) and Va = 1.8 m/s (to right) Every block is 25 kg. can you write a and b part's solutions seperatly ?
- the guy on images diving to the water. his limbs are fully tense when w1=0.22 rad/s what is w2=?5. Figure shows the schematic representation for the measurement of velocity of air (density = 1.2 kg/m³) through a constant-area duct using a pitot tube and a water-tube manometer. The differential head of water (density = 1000 kg/m³) in the two columns of the manometer is 10 mm. Take acceleration due to gravity as 9.8 m/s2. The velocity of air in m/s is Flow 10 mmDetermine the r-and 0-components of velocity and acceleration. 2.8' 3.9 370 Answers: V, = in./sec Va = in./sec i in./sec? in/sec? a, = ae = Find VA/B and vA/B- 315 m y Answers: VA/B = ! i+ i ! j) m/s VA/B = 25.104 m/s