Using the following characteristics, determine Bac at IB = 60 uA and VCe= 5V t/c (mA) (HA) V=IV VCE = 10 V VCE = 20 V N (Cutoff region) iCEO= Icao 45 65 75 85 la-0μA 20 VCE (V) 100 90- 80 70 GO 50 40 20 10 U 0.2 LLLLL 0.4 0.6 0.8 1.0 (b) VBE (V)

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Using the following characteristics,
determine Bac at IB = 60 uA and
VCe= 5V
c (mA)
+18 (HA)
Vce=1V
VCE = 10 V
VCE = 20 V
8
7
6
(Saturation region) 5
3
2
1
TVCE
O 45
O 65
O 75
O 85
90 μA
5
80 μA
E
70 μA
60 LA
THE
50 μA
*****
40 MA
+4
(Active region)
30 μA
20 μLA
| | | | | | | | | | | 10 μA
10
15
(Cutoff region)
CEO ICO
la=0μA
20 VCE (V)
100
90-
80
70
60
50-
40
30
20
10
0
L
0.2 0.4
0.6 0.8 1.0
(b)
VBE (V)
Transcribed Image Text:Using the following characteristics, determine Bac at IB = 60 uA and VCe= 5V c (mA) +18 (HA) Vce=1V VCE = 10 V VCE = 20 V 8 7 6 (Saturation region) 5 3 2 1 TVCE O 45 O 65 O 75 O 85 90 μA 5 80 μA E 70 μA 60 LA THE 50 μA ***** 40 MA +4 (Active region) 30 μA 20 μLA | | | | | | | | | | | 10 μA 10 15 (Cutoff region) CEO ICO la=0μA 20 VCE (V) 100 90- 80 70 60 50- 40 30 20 10 0 L 0.2 0.4 0.6 0.8 1.0 (b) VBE (V)
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