Using Le Chatelier’s principles, for the following equilibrium —- how do I predict the direction that the equilibrium will shift (towards the products or towards the reactants) for each of the following changes. Choosing either products or reactants. Or neither if the change would not affect the reaction... 3Cu(s) + 2NO3-(aq) + 8H+(aq) 3Cu2*(aq) +2NO(g) + 4H20(1) AH = -47 kcal/moleDecrease H2OReactantsProductsNeitherIncrease Cu2+ReactantsProductsNeitherDecrease pressureReactantsProductsNeitherIncrease CuReactantsProductsNeitherDecrease temperatureReactantsProductsNeither

Answered: Image /qna-images/answer/7378d74a-99e1-48ac-a6e3-964f670c8448.jpg

Using Le Chatelier’s principles, for the following equilibrium —- how do I predict the direction that the equilibrium will shift (towards the products or towards the reactants) for each of the following changes. Choosing either products or reactants. Or neither if the change would not affect the reaction...

Using Le Chatelier’s principles, for the following equilibrium —- how do I predict the direction that the equilibrium will shift (towards the products or towards the reactants) for each of the following changes. Choosing either products or reactants. Or neither if the change would not affect the reaction...

Introduction to General, Organic and Biochemistry

11th Edition

ISBN:9781285869759

Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres

Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres

Chapter7: Reaction Rates And Chemical Equilibrium

Section: Chapter Questions

Problem 7.42P

See similar textbooks

Similar questions

Calculate the heart of reaction (RH) for the chemical Reaction > Mg(NO₂) Mg + N + 30 Ma Mg. N₂ + 6mg 0 AH = -32811; using the following information 18 mg + Mg (NO3)2 > 2 mg + of Mqz N₂ 2 m² 0 3mg + Ng AH=4461kj AH - +1204 kj
H20 -OH H30* (1) XS LIAIH4 (2) H2O HO, он (1) XS CH;MgBr (2) H20
In one of the steps in this pathway fructose 1,6-biphosphate (F1,6BP) is converted to gylceraldehyde-3-phosphate (G-3-p) and dihydroxyacetone phosphate (DHAP). This reaction is catalyzed by the enzyme aldolase. For this reaction at 25 celcuius and Ph7 we have: Keq= 10-4M and Delta G = +5456 cal/mol Calculate the following: The concentration of F1, 6BP, DHAP and G-3-P at equilibrium when the initial F1,6BP is (A) 1M, (b) 10-2 M, (c) 2 X 10*4 M and (d) 10-5 M. I been trying to solve this problem but I dont even know where to begin with. Atleast help me with problem A, I would be able to guide myself through.
A research group discovers a new version of happyase, which they call happyase*, that catalyzes the chemical reaction HAPPY ⇌ SAD. The researchers begin to characterize the enzyme. (a) In the first experiment, with [Et] at 4 nM, they find that the Vmax is 1.6 μM s−1. Based on this experiment, what is the kcat for happyase*? (Include appropriate units.) (b) In another experiment, with [Et] at 1 nM and [HAPPY] at 30 μM, the researchers find that V0 = 300 nM s−1. What is the measured Km of happyase* for its substrate HAPPY? (Include appropriate units.) (c) Further research shows that the purified happyase used in the first two experiments was actually contaminated with a reversible inhibitor called ANGER. When ANGER is carefully removed from the happyase preparation and the two experiments repeated, the measured Vmax in (a) is increased to 4.8 μM s−1, and the measured Km in (b) is now 15 μM. For the inhibitor ANGER, calculate the values of α and α′. . (d) Based on the information given…
Draw the nullclines and find equilibria of the following extensions of the basic disease model. Find the nullclines and equilibria of this model when α = 2.0, µ = 1.0, and k = 4.0.
An enzyme catalyzed the reaction: S -> P has a AG" value of +4.8 kJ/mol. If you start with a solution containing 500 mM substrate [S] prior to the addition of enzyme and initiating the catalyzed reaction, then what is the substrate concentration [S] after reaching equilibrium? [R = 8.315 J/ mol* K; T = 25 C] NOTE - Provide your numeric answer in mM units as a TWO digit significant figure, and do NOT include units in your answer (report the numeric answer ONLY).
A research group discovers a neW version oI happyasee, which they nappyase", that catalyzes the chemical reaction HAPPY = SAD The researchers begin to characterize the enzyme. In the first experiment, with [E] at 4 nM, they find that the Vmax is 1.6 µM s-1. Based on this experiment, what is the kcat for happyase*? kcat 400 S In another experiment, with [E,] at 1 nM and [HAPPY] at 30 µM, the researchers find that Vo is equal to 300 nM s-1. What i the measured Km of happyase* for its substrate HAPPY? Km 10 x10–6 Incorrect Further research shows that the purified happyase* used in the first two experiments was actually contaminated with a reversible inhibitor called ANGER. When ANGER is carefully removed from the happyase* preparation, and the two experiments repeated, the measured Vmax increases to 4.8 µM s-, and the measured Km is now 15 µM. S For the inhibitor ANGER, calculate the values of a' and a. a' 2 Incorrect 2
The catalytic activity of an insect aminopeptidase was investigatedusing an artificial peptide substrate. The Vmax was 4.0 × 10-7 M/s and the KM was 1.4 × 10-4 M. The enzyme concentration used in the assay was 1.0 × 10-7 M. What is the value of kcat? 2.86 x 10-3 M 0.25 M/s 4.0 s-1 2.86 x 104 s/M 0.25 s-1
The bacterial load of a ketchup (pH-3.9) can be reduced from 6,000 units to 6 units in 15 minutes at 101 °C. (1) What is its D-value at 101 °C? (ii) How long should it be processed to sterilize it? (i) 3 minutes; (ii) 15 minutes (1) 3 minutes; (ii) 36 minutes (i) 5 minutes; (ii) 25 minutes (i) 5 minutes; (ii) 60 minutes
What is the balanced net inotic equation for: Pb+2(aq)+SO4-2 ----> ?
Rxn Reaction AH (kl/mol) exothermic/endothermic 1 Mg0 (s) + 2 HA (aq) 2 Mg (s) + 2 Ha(aq) з На (9) + 1/2 0, (9) + Mgd, (aq) + H,0 (0) → Mgl, (aq) + H2(g) H20 (0) 4 Mg (s) + 1/2 o, (g) Mg0 (s) Accepted value for AH
Which of the following reactions are written correctly? O 2HSO4laq) + 2NAOH(aq)→ 2NaSOa(aq) + 2H2O(U) H2SO4(aq) + 2 NaOH(aq)→Na2SO4(aq) + 2H20(0 O 2HCI(aq) + K2OH(aq) → 2KCI(aq) + H2O()