Use the two Fischer projections shown below to draw the Haworth projection of these two sugarslinked by an a(1-2) linkage, with the ß isoform of the ketohexose.HHㅎHOHHOHOHОНННОCH₂OH애,애애OHCH₂OHOHHOHOHOHIOHCH₂OHOHOH OHEngсаCH2OHCH2OHOHOHОНОНCH₂OHНOHННOHНTICH₂OHCH₂OHOHOHOHCH₂OHCH₂OHНCH₂OHCH₂OHОНOHOHНОOHHНOHCH₂OH

Carbohydrates are poly hydroxy aldehydes or ketones. They can be classified as monosaccharides,…

Answered: Use the two Fischer projections shown…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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Draw the (B1-->A1) linked dissacharide formed between the C3 epimer of B-D-glucose and the C2 epimer of a-D-galactose. Explain in 1-2 sentences why (or why not) a precipiate would be observed when mixing this dissacharide in an alkaline solution of copper.
Following are Fischer projections for a group of five-carbon sugars, all of which are aldopentoses. Identify the pairs that are enantiomers and the pairs that are epimers. (The sugars shown here are not all of the possible five-carbon sugars.) 1 СНО 2 СНО СНО Н-С—ОН Н-С—ОН Н—С—ОН Н-С—ОН НО —С—Н Н-С—ОН Н- С—ОН НО—С— Н НО—С—Н CH̟OH CH̟OH ČH̟OH в iоchemistry |61 STATE ATION Republic of the Philippines Romblon State University Romblan, Philippines 4 СНО 5 СНО 6 СНО НО—С—Н Н-С—ОН НО -С—Н Н—С—ОН НО -С—Н НО -С—Н H-C–OH Н-С—ОН НО—С—Н CH,OH ČH,OH CH,OH
The amount of branching (number of (α1→6) glycosidic bonds) in amylopectin can be determined by the following procedure. A sample of amylopectin is exhaustively methylated—treated with a methylating agent (methyl iodide) that replaces the hydrogen of every sugar hydroxyl witha methyl group, converting —OH to —OCH3 . All the glycosidic bonds in the treated sample are then hydrolyzed in aqueous acid, and the amount of 2,3-di-O-methylglucose so formed is determined.(a) Explain the basis of this procedure for determining the number of (α1→6) branch points in amylopectin. What happens to the unbranched glucose residues in amylopectin during the methylation and hydrolysis procedure?(b) A 258 mg sample of amylopectin treated as described above yielded 12.4 mg of 2,3-di-O-methylglucose. Determine what percentage of the glucose residues in the amylopectin contained an (α1→6) branch. (Assume that the average molecular weight of a glucose residue in amylopectin is 162 g/mol.)
What is the complete name of the following sugar? но он носн он Write out the words alpha and beta. This question is case-sensitive. Capitalize only the configuration designation, D or L, example: beta-D-glucopyranose.
Trehalose, also known as mycose, is a disaccharide found in certain mushrooms. It is composed of two a-D-glucose linked in a aa(1à1) glycosidic bond. Using Haworth projection, draw the structure of trehalose. Indicate whether it is reducing or non-reducing.
Draw both possible disaccharides of D-psicose and D-mannose that are joined by an α(1→4) glycosidic linkage. Are either of them now a reducing sugar?
D-Talose is a C2 epimer of D-galactose. Using the Fischer projection structure, draw the product of reaction ofD-talose with the given reagent or enzyme and write the systematic name of the product. 1. 2,4-DNP 2. Reaction with aminotransferase and then acetyltransferase at C4
Following are Fischer projections for a groupof five-carbon sugars, all of which are aldopentoses. Identify thepairs that are enantiomers and the pairs that are epimers. (Thesugars shown here are not all of the possible five-carbon sugars.)
Following are Fischer projections for a group of five-carbon sugars, all of which are aldopentoses. Identify the pairs that are enantiomers and the pairs that are epimers. (The sugars shown here are not all of the possible five-carbon )
Draw the enediolate intermediate of the ribulose-5-phosphate isomerasereaction (Ru5P → R5P).
gal(a1→6)gal(a1→6)glc(a1→2B)fru. Which of the complete IUPAC of this tetrasaccharide? a-D-galactopyranosyl-(1→6)-ß-D-galactopyranosyl-(1→6)- a-D-glucopyranosyl-(1→2)-B-fructofuranose a-D-galactopyranosyl-(1→6)- a-D-galactopyranosyl-(1→6)- a-D-glucopyranosyl-(1→2)-ß-fructofuranoside a-D-galactopyranosyl-(1→6)- a-D-galactopyranosyl-(1→6)- a-D-glucopyranosyl-(1<→2)-ß-fructofuranose a-D-galactopyranosyl-(1→6)-B-D-galactopyranosyl-(1→6)- a-D-glucopyranosyl-(1→2)-ß-fructofuranoside
One can identify phenylketonurics and PKU carriers (heterozygotes) by means of a phenylalanine tolerance test. One injects a large dose of pheny- lalanine into the bloodstream and measures its clearance from the blood by measuring serum phenylalanine levels at regular intervals. Sketch curves showing relative blood phenylalanine concentration versus time that you would expect to be displayed by (a) a PKU patient, (b) a heterozygote, and (c) a normal individual. What kind of tolerance test could you devise to distinguish between PKU resulting from either phenylalanine hydroxylase deficiency or dihydropteridine reductase deficiency?

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