Use the given transformation x = 2u+v,y=u+ 2v to evaluate the integral [] (2y = x) dA where D is the trianglar region with vertices (0.0). (2. 1). (1.2).

Use the given transformation to evaluate the given integral, where R is the parallelogram with vertices (-1, 2), (1, -2), (2, -1), and (0, 3). L = ff (6x + 6y) dA; L = x = = } (u + v), y = }} (v - 2u)