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Use the equation for the height of an object (in meters) at time t (in seconds) given below where so is the initial height and vo is the initial velocity. s(t) = so + vot 4.9t? An object is tossed into the air vertically from ground level and returns to Earth 9.9 seconds later. Determine the exact velocity at time t =3.9.

Use the equation for the height of an object (in meters) at time t (in seconds) given below where so is the initial height and vo is the initial velocity. s(t) = so + vot 4.9t? An object is tossed into the air vertically from ground level and returns to Earth 9.9 seconds later. Determine the exact velocity at time t =3.9.

Physics for Scientists and Engineers, Technology Update (No access codes included)
Physics for Scientists and Engineers, Technology Update (No access codes included)
9th Edition
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter3: Vectors
Section: Chapter Questions
Problem 3.62AP: After a ball rolls off the edge of a horizontal table at time t = 0, its velocity as a function of...
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Use the equation for the height of an object (in meters) at timet (in seconds) given below where so is the initial height and vo is the initial velocity. s(t) = 80 + vot – 4.9t² An object is tossed into the air vertically from ground level and returns to Earth 9.9 seconds later. Determine the exact velocity at time t =3.9.
Transcribed Image Text:Use the equation for the height of an object (in meters) at timet (in seconds) given below where so is the initial height and vo is the initial velocity. s(t) = 80 + vot – 4.9t² An object is tossed into the air vertically from ground level and returns to Earth 9.9 seconds later. Determine the exact velocity at time t =3.9.
Expert Solution
Step 1

Given information:

The position from which the object is tossed(S0) = 0 m (ground)

The time it takes to return to the earth (t) = 9.9 sec

The time at which the velocity is required (t') = 3.9 sec 

Given equation of motion:

s(t) = S0+v0t-4.9t

The total displacement at the end is "Zero" i.e. when the body reaches back to ground. we can write this as:

s(t) = S0+v0t-4.9t2=0v0=4.9(9.9)=48.51 m/s  

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