Use material balance based on species method to calculate the products from reactor, where the two following chemical reaction take places; 2 C10H22 → 2 C10H10 + 12 H2 ………………………(1) 2 C10H22 + 2 H2 → 4 C5H12 ………………………(2) If the flow rate of the fed into reactor is 350 kgmol , consist of a mixture of 79 % mole C10H22 and the rest inert N2 gas. The fraction conversion of the C10H22 is 0.45 and the yield is 0.39, (where yield is the ratio of the mole of C10H10 produced to the mole of C10H22 fed into reactor).
Use material balance based on species method to calculate the products from reactor, where the two following chemical reaction take places; 2 C10H22 → 2 C10H10 + 12 H2 ………………………(1) 2 C10H22 + 2 H2 → 4 C5H12 ………………………(2) If the flow rate of the fed into reactor is 350 kgmol , consist of a mixture of 79 % mole C10H22 and the rest inert N2 gas. The fraction conversion of the C10H22 is 0.45 and the yield is 0.39, (where yield is the ratio of the mole of C10H10 produced to the mole of C10H22 fed into reactor).
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Use material balance based on species method to calculate the products from reactor, where the two
following chemical reaction take places;
2 C10H22 → 2 C10H10 + 12 H2 ………………………(1)
2 C10H22 + 2 H2 → 4 C5H12 ………………………(2)
If the flow rate of the fed into reactor is 350 kgmol , consist of a mixture of 79 % mole C10H22 and the rest
inert N2 gas.
The fraction conversion of the C10H22 is 0.45 and the yield is 0.39, (where yield is the ratio of the mole of
C10H10 produced to the mole of C10H22 fed into reactor).
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