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Use a range-based for loop in C++ to loop through a given vector of integers and determine how many elements in the vector are evenly divisible by either 3 or by 5. The final result should be stored in an integer variable named count. Use the following vector vec of integers (hardcoded) in your program. vector vec {1,3,5,15,16,17,18,19,20,21,25,26,27,30,50,55,56,58,100,200,300,400,500,600,700}; Output: First display the integers that are evenly divisible by 3 or 5, then display the count

Use a range-based for loop in C++ to loop through a given vector of integers and determine how many elements in the vector are evenly divisible by either 3 or by 5. The final result should be stored in an integer variable named count. Use the following vector vec of integers (hardcoded) in your program. vector vec {1,3,5,15,16,17,18,19,20,21,25,26,27,30,50,55,56,58,100,200,300,400,500,600,700}; Output: First display the integers that are evenly divisible by 3 or 5, then display the count

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Use a range-based for loop in C++ to loop through a given vector of integers and determine how many elements in the vector are evenly divisible by either 3 or by 5.

The final result should be stored in an integer variable named count.

Use the following vector vec of integers (hardcoded) in your program.

vector<int> vec {1,3,5,15,16,17,18,19,20,21,25,26,27,30,50,55,56,58,100,200,300,400,500,600,700};

Output: First display the integers that are evenly divisible by 3 or 5, then display the count.

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