Hand written solutions are strictly prohibited. use AH° formation valuesfor theneutralizationH₂SO4 (aq) + 2NaOH(aq) 2₂0 (x) + Nozsecs)сад)Formation values:4₂504 = -90 7.5H₂0=AH =-to calculate ANDfollowing reaction285,8NaOH = -469.6Na₂SO4 = -1389. 47

Answered: Image /qna-images/answer/c62018c2-731e-4758-a9a9-88a701600483.jpg

Use A Hº formation values neutralization for the 1₂ SO 4 caq) + 2NaOH cqg) -> 2H₂0 (x) + Naz Songs] Formation values: 4₂504 = -90 7.5 H₂O = - 285.8 to calculate AND following reaction AH - NaOH = -469.6 Na ₂ So = -1389. 47

Use A Hº formation values neutralization for the 1₂ SO 4 caq) + 2NaOH cqg) -> 2H₂0 (x) + Naz Songs] Formation values: 4₂504 = -90 7.5 H₂O = - 285.8 to calculate AND following reaction AH - NaOH = -469.6 Na ₂ So = -1389. 47

Chemistry & Chemical Reactivity

10th Edition

ISBN:9781337399074

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Chapter20: Environmental Chemistry-earth's Environment, Energy, And Sustainability

Section: Chapter Questions

Problem 41PS

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Concept explainers

Group 13 Elements

In the periodic table, group 13 elements exist in the first p-block. There are six elements present in group 13, which include boron (B), aluminum (Al), gallium (Ga), indium (In), thallium (Tl), and element 113 (ununtrium, (Uut)). Group 13 elements are also designated as the boron family.

Question

Hand written solutions are strictly prohibited.

use AH° formation values
for the
neutralization
H₂SO4 (aq) + 2NaOH(aq) 2₂0 (x) + Nozsecs)
сад)
Formation values:
4₂504 = -90 7.5
H₂0=
AH =
-
to calculate AND
following reaction
285,8
NaOH = -469.6
Na₂SO4 = -1389. 47

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