need help Engineering of Materials ReviewDetermine the modulus of resilience.Express your answer to three significant figures.The stress-strain diagram for an aluminum alloy specimen having an originaldiameter of 0.5 in. and a gage length of 2 in. is shown in the figurebelow. (Figure 1)VO A£¢ f vec(u, )approx = 1000in-lbinSubmitPrevious Answers Request AnswerX Incorrect; Try Again; 9 attempts remainingPart BFigure1 of 1Determine the modulus of toughness.Express your answer to three significant figures.o (ksi)70vec6050in-kip(ut)approx = 940in33020SubmitPrevious Answers Request Answer10-€ (in. /in.)0 0.02 0.04 0.06 0.08 0.10 0.12 0.14 0.16 0.18 0,20 0025 0.0050.0075 0.01 0,01250.0150.0175 0.02 0,0255 0.025X Incorrect; Try Again; 9 attempts remainingP PearsonCopyright © 2022 Pearson Education Inc. All rights reserved. | Terms of Use | Privacy Policy | Permissions | Contact Us |

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(u,)Japprox = 1000 Submit Previous Answers Request Answer X Incorrect; Try Again; 9 attempts remaining • Part B Determine the modulus of toughness. Express your answer to three significant figures. ν ΑΣφ vec (u.)approx = 9

(u,)Japprox = 1000 Submit Previous Answers Request Answer X Incorrect; Try Again; 9 attempts remaining • Part B Determine the modulus of toughness. Express your answer to three significant figures. ν ΑΣφ vec (u.)approx = 9

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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a . Sketch stress strain curve if the result shown in table represent the force and extension happened in steel, and show Mechanical properties that we get from tensile test on curve? (10p)Note : Lo=80 mm , Do=10 mm , use excel to plot the curve ExtensionLoad(mm) (N)0 0.900.83 4694.341.67 4831.412.50 4781.083.33 4918.834.17 4926.585.00 5257.075.83 5437.016.66 5575.888.33 5775.189.16 5847.5210.83 5965.4111.67 6010.5312.50 6042.5713.33 6072.2614.16 6092.9315.00 6113.2416.67 6140.3617.50 6146.3718.33 6148.1419.16 6149.1725.00 5940.2125.83 5675.3326.67 4725.52b. What is meant by modulus of rigidity? if it increases what does happen to material? (2p)
Review Data taken from a stress-strain test for a ceramic are No elements selected o(ksi) given in the table. The curve is linear between the origin and the first point. 50 40 30 Figure 1 of 1 20 10 σ (ksi) e (in./in.) ex 10-*(in./in.) 0.5 1.0 1.5 2.0 25 33.2 0.0006 45.5 0.0010 Press (ENTER to select this element. Press (ESc to return to the main menu. Press (CTRL+Q) to quit the application. 49.4 0.0014 51.5 0.0018 53.4 0.0022
1. Plot the engineering stress & strain diagram of an alloy having a tensile test result found in Table 1. The tensile test specimen has a diameter of 12.5mm and a gage length of 50.0mm. The given alloy is used to make a 30.0mm diameter cylinder, which is placed inside a hardened circular steel casement with a 30.01mm inner diameter. Table 1: Tensile test results of an alloy Change In Length (mm) Change In Diameter (mm) Load (kN) 0.000 0.0000 0.0000 4.364 0.0254 0.0019 -0.0057 13.092 0.0762 21.819 0.1270 0.0095 30.547 32.729 0.1778 0.7620 34.911 3.0480 30.01 mm O F Rigid Plate Cylindrical Alloy -Steel casement Figure k Section view of the steel casement encapsulating the cylindrical alloy 2. Determine the required minimum value of F such that the cylindrical alloy would touch the walls of the steel casement.
1. Plot the engineering stress & strain diagram of an alloy having a tensile test result found in Table 1. The tensile test specimen has a diameter of 12.5mm and a gage length of 50.0mm. The given alloy is used to make a 30.0mm diameter cylinder, which is placed inside a hardened circular steel casement with a 30.01mm inner diameter. Table 1: Tensile test results of an alloy Change In Length (mm) Change In Diameter (mm) Load (kN) 0.000 0.0000 0.0000 4.364 0.0254 -0.0019 13.092 0.0762 -0.0057 21.819 0.1270 -0.0095 30.547 0.1778 32.729 0.7620 34.911 3.0480 30.01 mm Ø F Rigid Plate Cylindrical Alloy - Steel casement Figure 1: Section view of the steel casement encapsulating the cylindrical alloy 2. Determine the required minimum value of F such that the cylindrical alloy would touch the walls of the steel casement.
Stress Strain Diagram The Data shown in the table have been obtained from a tensile test conducted on a high-strength steel. The test specimen had a diameter of 0.505 inch and a gage length of 2.00 inch. Using software. plot the Stress-Strain Diagram for this steel and determine its: A= TTdT(050s A %3D 1. Proportional Limit, 2. Modulus of Elasticity, 3. Yield Strength (SY) at 0.2% Offset, 4. Ultimate Strength (Su), 5. Percent Elongation in 2.00 inch, 6. Percent Reduction in Area, 7. Present the results (for Steps 1-6) in a highly organized table. e Altac ie sheet (as problelle 4 A = 0.2.002 BEOINNING of the effort Elongation (in) Elongation (In) Load Load #: #3 (Ib) (Ib) 1 0.0170 15 12,300 0.0004 1,500 16 12,200 0.0200 0.0010 3. 3,100 17 12,000 0.0275 0.0016 4,700 18 13,000 0.0335 5. 6,300 0.0022 19 15,000 0.0400 0.0026 6. 8,000 20 16,200 0.055 0.0032 9,500 21 17,500 0.0680 0.0035 8. 11,000 22 18,800 0.1080 0.0041 11,800 23 19,600 0.1515 0.0051 24 20,100 0.2010 10 12,300 0.0071 25…
Question A cylindrical specimen of metal having a diameter of 12.88 mm and a gauge length of 63.50 mm is tested using a tensile testing machine. The elongation measurement are recorded in Table 3. nPlot the stress-strain curve on the graph paper provided based on data in Table 3 Based on the stress-strain curved plotted in (i): Compute the modulus of elasticity Determine the yield strength at a strain offset of 0.002. Determine the tensile strength Determine the ductility in percent elongation and percent area reduction Table 3: Load-elongation readings for a metal specimen Jadual 3: Bacaan beban pemanjangan untuk statu spesimen logam) Load (N) Elongation (mm) 1380 0.03 2780 0.06 5630 0.12 7430 0.2 8140 0.25 9870 0.64 12850 1.91 14100 3.18 14340 4.45 13830 5.72 12500 6.99 Fracture
640 480 160 0.002 0,004 0.006 0.008 0.010 Strain (mm/mm) A tensile test specimen of Aluminum alloy having a gauge length of 280 mm was tested to fracture. Stress and strain data obtained during the test are shown in the attached Figure. **Answers are approximate - do your best to read the graph. Determine: (a) the modulus of elasticity in GPa (4sigs). Enter this value into D2L answer box. (b) the proportional limit in MPa (3sigs). (c) the ultimate strength in MPa (3sigs). (d) Ductility of material based on percent elongation. (3sigs) Your Answer: Stress (MPa)
Data taken from a stress-strain test for a ceramic are given in the table. The curve is linear between the origin and the first point. Figure σ (ksi) 0 33.2 45.5 49.4 51.5 53.4 € (in./in.) 0 0.0006 0.0010 0.0014 0.0018 0.0022 < 1 of 1 Part A Plot the stress-strain diagram. (Figure 1) +SGA0 No elements selected σ(ksi) Submit Request Answer 50 40 30+ 20 10 0.5 1.0 1.5 2.0 2.5 €x 10-³(in./in.) ? Select the elements from the list and add them to the canvas setting the appropriate attributes. Press [CTRL+M) to get to the main menu.
Choose the LETTER from the stress strain graph that matches the stress strain graph attributes listed below.
Given the following stress-strain graph:a. is the modulus of elasticity of "A-514" greater, less or equal to the one of "A-572"?b. from the previous question, make an estimatio for both of them, check that the graphic comes in %c. If we were to test these materials in a universal tension equipment, which one would withstand more load?d. If we were to test these materials in a universal tension machine, which one would elongate the most before fracturing? would elongate the most before fracturing? e. Of the 6 materials shown, do any behave as brittle materials? f.
The following data was obtained as a result of tensile testing of a standard 0.505 inch diameter test specimen of magnesium. After fracture, the gage length is 2.245 inch and the diameter is 0.466 inch. a). Calculate the engineering stress and strain values to fill in the blank boxes and plot the data. Load(lb) Gage Length (in) Stress (kpsi) Strain 0 2 1000 2.00154 2000 2.00308 3000 2.00462 4000 2.00615 5000 2.00769 5500 2.014 6000 2.05 6200 (max) 2.13 6000 (fracture) 2.255 b). Calculate the modulus of elasticity c). If another identical sample of the same material is pulled only to 6000 pounds and is unloaded from there, determine the gage length of the sample after unloading.
The following data were obtained from a standard tensile stress test on a mild steel specimen. Graph the result and determine proportional limit stress and Young’s Modulus.