u ? }y? 2 E3 = //fw E₁₂ = fo E₁ = /ho E₁₁ = 1/1 fo + + 0 √ax 5

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The image below indicates that as v increases, the probability moves to the edges of the potential

What is the practical significance of this?

u ?
}y?
2
E3 = //fw
E₁₂ = fo
E₁ = /ho
E₁₁ = 1/1 fo
+
+
0
√ax
5
Transcribed Image Text:u ? }y? 2 E3 = //fw E₁₂ = fo E₁ = /ho E₁₁ = 1/1 fo + + 0 √ax 5
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