Typically, software designed for address space configurations of zero, one, or two bytes is lengthier (contains more instructions). Why?
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Typically, software designed for address space configurations of zero, one, or two bytes is lengthier (contains more instructions). Why?
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- If a microprocessor has a cycle time of 0.5 nanoseconds, what’s the processor clock rate? If the fetch cycle is 40% of the processor cycle time, what memory access speed is required to implement load operations with zero wait states and load operations with two wait states?A(n) __________ is a storage location implemented in the CPU.Software written for address space layouts of zero, one, or two bytes is often longer (have more instructions). Why?
- Programs designed for zero-address architecture, one-address architecture, or two-address architecture are more likely to be longer (have more instructions). Why?Programs designed for zero-address, one-address, or two-address architecture tend to be lengthier (have more instructions). Why?When it comes to program length, programs created for zero-address architecture are more likely to be longer (have more instructions) than programs developed for one or two-address architectures. Why?
- For 8086 microprocessor, the stack segment may have a memory block of a maximum of 32K bytes O 64K bytes O 16K bytes O Option 4 OPrograms for zero-, one-, or two-address architectures are generally longer (have more instructions). Why?The memory unit of a computer has 2M words of 32 bits each. The computer has an instruction format with 4 fields: an opcode field; a mode field to specify 1 of 4 addressing modes; a register address field to specify one of 9 registers; and a memory address field. Assume an instruction is 32 bits long. Answer the following: d) How large is the opcode field?
- Describe the concept of pipelining in computer architecture and its benefits.It is more probable that programs developed for zero-address, one-address, or two-address architecture will be lengthier (have more instructions). Why?The memory unit of a computer has 256K words of 32 bits each. The computer has an instruction format with four fields: an opcode field; a mode field to specify one of seven addressing modes; a register address field to specify one of 60 registers; and a memory address field. Assume an instruction is 32 bits long. Answer the following:Q.) How large must the address field be?