Two types of plastic are suitable for an electronics component manufacturer to use. The breaking strength of this plastic is important. It is known that o₂ = ₂ = 1.0 psi. From a random sample size n₁ = 10 and n₂ = 12, you obtain ₁ = 162.5 and ₂ = 155.0. The company will not adopt plastic 1 unless its mean breaking strength exceeds that of plastic 2 by at least 10 psi. Based on the sample information, should the company use plastic 1? Use a = 0.05.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
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ISBN:9780079039897
Author:Carter
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Chapter10: Statistics
Section10.1: Measures Of Center
Problem 9PPS
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Two types of plastic are suitable for an electronics component manufacturer to use. The breaking
strength of this plastic is important. It is known that σ₁ = ₂ = 1.0 psi. From a random sample
size n₁ = 10 and n₂ = 12, you obtain ₁ = 162.5 and ₂ = 155.0. The company will not adopt
plastic 1 unless its mean breaking strength exceeds that of plastic 2 by at least 10 psi.
Based on the sample information, should the company use plastic 1? Use a = 0.05.
a. Reject the Null Hypothesis. Zo = -5.84
b. None among the choices
O c. Fail to reject the Null Hypothesis. P-value > 0.05
d. Fail to reject the Null Hypothesis. Zo < 1.65
Transcribed Image Text:Two types of plastic are suitable for an electronics component manufacturer to use. The breaking strength of this plastic is important. It is known that σ₁ = ₂ = 1.0 psi. From a random sample size n₁ = 10 and n₂ = 12, you obtain ₁ = 162.5 and ₂ = 155.0. The company will not adopt plastic 1 unless its mean breaking strength exceeds that of plastic 2 by at least 10 psi. Based on the sample information, should the company use plastic 1? Use a = 0.05. a. Reject the Null Hypothesis. Zo = -5.84 b. None among the choices O c. Fail to reject the Null Hypothesis. P-value > 0.05 d. Fail to reject the Null Hypothesis. Zo < 1.65
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