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Two Stations A and B are 540 m. apart. From the following triangulation stations C and D on opposite sides of AB, the following angles were observed Angle ACD - 54°12' Angle DCB - 41°24' Angle ADC - 49°18' Angle BDC - 4712' 34*72141 *24 540 m 49*18';47'12', Find Distance CD 481.30 m 480.30 m 479.30 m 478.30 m

Two Stations A and B are 540 m. apart. From the following triangulation stations C and D on opposite sides of AB, the following angles were observed Angle ACD - 54°12' Angle DCB - 41°24' Angle ADC - 49°18' Angle BDC - 4712' 34*72141 *24 540 m 49*18';47'12', Find Distance CD 481.30 m 480.30 m 479.30 m 478.30 m

Algebra: Structure And Method, Book 1
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter12: Quadratic Functions
Section12.8: Joint And Combined Variation
Problem 4E
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Using Triangulation and Trilateration

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Two Stations A and B are 540 m. apart. From the following triangulation stations C and D on opposite sides of AB, the following angles were observed Angle ACD - 5412' Angle DCB - 41°24' Angle ADC - 49°18" Angle BDC - 47'12 54°72'141 °24' 540 m 49*18';47*12', Find Distance CD 481.30 m 480.30 m 479.30 m 478.30 m
Transcribed Image Text:Two Stations A and B are 540 m. apart. From the following triangulation stations C and D on opposite sides of AB, the following angles were observed Angle ACD - 5412' Angle DCB - 41°24' Angle ADC - 49°18" Angle BDC - 47'12 54°72'141 °24' 540 m 49*18';47*12', Find Distance CD 481.30 m 480.30 m 479.30 m 478.30 m
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