Two catalysts in a batch chemical process are being compared for their effect on the output of the process reaction. A sample of 13 batches was prepared using catalyst 1 and gave an average yield of 82 with a sample standard deviation of 6. A sample of 12 batches was prepared using catalyst 2 and gave an average yield of 75 and a sample standard deviation of 4. Find a 95% confidence interval for the difference between the population means, assuming that the populations are approximately normally distributed with equal variances. Click here to view page 1 of the table of critical values of the t-distribution. Click here to view page 2 of the table of critical values of the t-distribution. ... Let μ₁ be the population mean for catalyst 1 and let μ₂ be the population mean for catalyst 2. The confidence interval is

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Two catalysts in a batch chemical process are being compared for their effect on the
output of the process reaction. A sample of 13 batches was prepared using catalyst 1
and gave an average yield of 82 with a sample standard deviation of 6. A sample of 12
batches was prepared using catalyst 2 and gave an average yield of 75 and a sample
standard deviation of 4. Find a 95% confidence interval for the difference between the
population means, assuming that the populations are approximately normally distributed
with equal variances.
Click here to view page 1 of the table of critical values of the t-distribution.
Click here to view page 2 of the table of critical values of the t-distribution.
Let μ₁ be the population mean for catalyst 1 and let μ₂ be the population mean for
catalyst 2.
The confidence interval is |<H₁-H₂ <.
(Round to two decimal places as needed.)
Transcribed Image Text:Two catalysts in a batch chemical process are being compared for their effect on the output of the process reaction. A sample of 13 batches was prepared using catalyst 1 and gave an average yield of 82 with a sample standard deviation of 6. A sample of 12 batches was prepared using catalyst 2 and gave an average yield of 75 and a sample standard deviation of 4. Find a 95% confidence interval for the difference between the population means, assuming that the populations are approximately normally distributed with equal variances. Click here to view page 1 of the table of critical values of the t-distribution. Click here to view page 2 of the table of critical values of the t-distribution. Let μ₁ be the population mean for catalyst 1 and let μ₂ be the population mean for catalyst 2. The confidence interval is |<H₁-H₂ <. (Round to two decimal places as needed.)
A random sample of size n₁ = 23, taken from a normal population with a standard
deviation o₁ = 6, has a mean x₁ = 89. A second random sample of size n₂ = 39, taken
from a different normal population with a standard deviation ₂ = 4, has a mean x₂ = 31.
Find a 96% confidence interval for μ₁ −μ₂.
Click here to view page 1 of the standard normal distribution table.
Click here to view page 2 of the standard normal distribution table.
The confidence interval is <H₁ - H₂<·
(Round to one decimal place as needed.)
Transcribed Image Text:A random sample of size n₁ = 23, taken from a normal population with a standard deviation o₁ = 6, has a mean x₁ = 89. A second random sample of size n₂ = 39, taken from a different normal population with a standard deviation ₂ = 4, has a mean x₂ = 31. Find a 96% confidence interval for μ₁ −μ₂. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. The confidence interval is <H₁ - H₂<· (Round to one decimal place as needed.)
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