Workout solution Electric Currents and Circuits Worksheet 1Student Name:Group Members:Two 20 cm x 20 cm plates of aluminum, separated by a distance of 1.0 cm, are charged by a 100V battery. A slab of Teflon (K = 2.0) fills the space between the plates.1. What is the capacitance of this capacitor?AVDielectricAVe+Qo2. What is the voltage of this capacitor?CS Scanned with CamScanner|||| | | I Electric Currents and Circuits Worksheet 13. How much charge is on each plate of this capacitor?4. What is the electric field strength between the plates of this capacitor?CS Scanned with CamScanner

Answered: Image /qna-images/answer/04abce18-8a4e-4463-b3e4-a97c53cc8b51.jpg

Two 20 cm x 20 cm plates of aluminum, separated by a distance of 1.0 cm, are charged by a 100 V battery. A slab of Teflon (K = 2.0) fills the space between the plates. 1. What is the capacitance of this capacitor? AV Dielectric AVe +Q 2. What is the voltage of this capacitor?

Two 20 cm x 20 cm plates of aluminum, separated by a distance of 1.0 cm, are charged by a 100 V battery. A slab of Teflon (K = 2.0) fills the space between the plates. 1. What is the capacitance of this capacitor? AV Dielectric AVe +Q 2. What is the voltage of this capacitor?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter16: Electrical Energy And Capacitance

Section: Chapter Questions

Problem 35P: a parallel-plate capacitor with area 0.200 m2 and plate separation of 3.00 mm is connected to a...

See similar textbooks

Similar questions

Unreasonable Results (a) What is the final speed of an electron accelerated from rest through a voltage of 25.0 MV by a negatively charged Van de Graaff terminal? (b) What is unreasonable about this result? (C) Which assumptions are responsible?
(a) Would life be different if the electron were positively charged and the proton were negatively charged? (b) Does the choice of signs have any bearing on physical and chemical interactions? Explain your answers.
Three capacitors having capacitances of 8.40, 8.40, and 4.20F , respectively, are connected in series across a 36.0-V potential difference. (a) What is the charge on the 4.20F capacitor? (b) The capacitors are disconnected from the potential difference without allowing them to discharge. They are then reconnected in parallel with each other with the positively charged plates connected together. What is the voltage across each capacitor in the parallel combination?
To form a helium atom, an alpha particle that contains two protons and two neutrons is fixed at one location, and two electrons are brought in from far away, one at a time. The first electron is placed at 0.6001010 m from the alpha particle and held there while the second electron is brought to 0.6001010 m from the alpha particle on the other side from the first electron. See die final configuration below, (a) How much work is done in each step? (b) What is the electrostatic energy of die alpha particle and two electrons in the final configuration?
a parallel-plate capacitor with area 0.200 m2 and plate separation of 3.00 mm is connected to a 6.00-V battery. (a) What is the capacitance? (b) How much charge is stored on the plates? (c) What is the electric field between the plates? (d) Find the magnitude of the charge density on each plate. (e) Without disconnecting the battery, the plates are moved farther apart. Qualitatively, what happens to each of the previous answers?
A parallel-plate capacitor has charge of magnitude 9.00F on each plate and capacitance 3.00F when there is air between the plates. The plates are separated by 2.00 mm. With the charge on the plates kept constant, a dielectric with =5 . is inserted between the plates, completely filling the volume between the plates, (a) What is the potential difference between the plates of the capacitor, before and after the dielectric has been inserted? (b) What is the electrical field at the point midway between the plates before and after the dielectric is inserted?
When a 360-nF air capacitor is connected to a power supply, the energy stored in the capacitor is 18.5J . While the capacitor is connected to the power supply, a slab of dielectric is insetted that completely fills die space between the plates. This increases the stored energy by 23.2J . (a) What is the potential difference between the capacitor plates? (b) What is die dielectric constant of the slab?
A parallel plate capacitor in air is constructed with two 32 cm x 32 cm square conductors separated by 4 mm. a) Determine the value of the capacitance of this parallel plate capacitor. b) This capacitor is placed across a 22 V battery and allowed to fully charge. What is the value of this charge? To continue, please enter your answer in b) in units of nC. Round your answer to 1 decimal place.
An air filled with 50μF has a voltage of 10V. An insulator with a dielectric constant of 4.0 is inserted between the metal plates. 1. Calculate the capacitance. 2. What is the new voltage across the capacitor? 3. Calculate the original charge on the capacitor. 4. How much charge is currently on the capacitor?
Consider the two charged conducting plates shown in Figure 3, they are very close to one another. a. Calculate the magnitude and direction of the electric field at point H (it’s at the center of the gap).b. Calculate the surface charge density on the plate F.c. If plates F and G are square-shaped, and both have a surface area of 9 m2, calculate the capacitanceof this configuration.d. What is the total electric potential energy of this charge configuration?
A. If you could keep a constant charge +Q on one plate and charge -Q on the other plate, while the wire in the figure is connected, would charge flow through the wire? B. Would the charge flow continuosly? Explain C. Would the potential difference between the plates change or remain constant? Explain.
A parallel-plate capacitor is constructed from two square sheets of aluminum foil, each of dimensions 0.21 m × 0.21 m. The plates are separated by an air gap of 1.8 mm. a. Calculate the capacitance of the capacitor, in picofarads. b. What will the capacitance be, in picofarads, if the plate separation is doubled? c. Calculate what the capacitance will be, in picofarads, if the plates are halved in area while keeping the original plate separation.