truss structure is loaded as shown in Fig. 1. The truss members are made of A36 ste = 36 ksi). All the members are made up of two 3.0"x5.0" (each) parallel flat bars. All the join nave bolt connection (pin connection), acting in double shear. The diameter of all the bolts is 3.0". Determine, The average normal and shear stresses in bars AB, and Cl and the shear stress in pin H. The average normal and shear strain in AB, and CI and shear strain in pin H (Given, E = 29x106 psi, G = 11x 106 psi) 4k 4k B D IH or GH 8 ft A Pin H H. 4k 6 @8 ft = 48 ft

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter1: Tension, Compression, And Shear
Section: Chapter Questions
Problem 1.9.3P: A tie-down on the deck of a sailboat consists of a bent bar boiled at both ends, as shown in the...
icon
Related questions
Question
A steel truss structure is loaded as shown in Fig. 1. The truss members are made of A36 steel (f,
= 36 ksi). All the members are made up of two 3.0"x5.0" (each) parallel flat bars. All the joints
have bolt connection (pin connection), acting in double shear. The diameter of all the bolts is
3.0". Determine,
•The average normal and shear stresses in bars AB, and Cl and the shear stress in pin H.
•The average normal and shear strain in AB, and CI and shear strain in pin H (Given, E =
29x106 psi, G = 11x 106 psi)
4k
4k
C
IH or GH
8 ft
A
Pin H
JT
H
4k
6 @ 8 ft = 48 ft
Fig. 1
Transcribed Image Text:A steel truss structure is loaded as shown in Fig. 1. The truss members are made of A36 steel (f, = 36 ksi). All the members are made up of two 3.0"x5.0" (each) parallel flat bars. All the joints have bolt connection (pin connection), acting in double shear. The diameter of all the bolts is 3.0". Determine, •The average normal and shear stresses in bars AB, and Cl and the shear stress in pin H. •The average normal and shear strain in AB, and CI and shear strain in pin H (Given, E = 29x106 psi, G = 11x 106 psi) 4k 4k C IH or GH 8 ft A Pin H JT H 4k 6 @ 8 ft = 48 ft Fig. 1
Expert Solution
steps

Step by step

Solved in 3 steps with 2 images

Blurred answer
Knowledge Booster
Stress
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Mechanics of Materials (MindTap Course List)
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:
9781337093347
Author:
Barry J. Goodno, James M. Gere
Publisher:
Cengage Learning