a.) Anambulance moving awayfromyoutowardcliffant12 m/s emitssoundarunningvelocityatfieauency 1000Hz. YauaretowardthecliffreqvenuywithofaZ mls, whatyouambulunce? Speed ofdohearcomingdirectly from34 0mls.thesoundisaj97zb,)৭27C.)1034d.71043b.) Whatreflectedfreauency do you herrcliff?hearfor saindfromtheb.) 1043i.)972 d.) az7

Answered: trom a.) An ambulunce moving away…

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter28: Special Relativity

Section: Chapter Questions

Problem 17PE: (a) How fast would an athlete need to be running for a 100-m race to look 100 yd long? (b) Is the...

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Question

a.) An
ambulance moving away
from
you
toward
cliff
ant
12 m/s emits
sound
a
running
velocity
at
fieauency 1000Hz. Yau
are
toward
the
clif
freqvenuy
with
of
a
Z mls, what
you
ambulunce? Speed of
do
hear
coming
directly from
34 0mls.
the
sound
is
aj97z
b,)৭27
C.)1034
d.71043
b.) What
reflected
freauency do you herr
cliff?
hear
for saind
from
the
b.) 1043
i.)972 d.) az7

Expert Solution

Step 1

(a)

The frequency of the sound coming directly from the ambulance can be determined as follows.

$\begin{array}{rcl} f & = & (\frac{v + v_{o}}{v - v_{s}}) f_{0} \\ = & (\frac{(340 m / s) + (2 m / s)}{(340 m / s) - (12 m / s)}) (1000 Hz) \\ = & 1042.68 Hz \\ \approx & 1043 Hz \end{array}$

Therefore, the option (d) ‘1043 Hz’ is correct

Step 2

(b)

Determine the frequency of the sound coming from the ambulance towards the cliff as follows.

$\begin{array}{rcl} f'_{0} & = & (\frac{v}{v + v_{s}}) f_{0} \\ = & (\frac{(340 m / s)}{(340 m / s) + (12 m / s)}) (1000 Hz) \\ = & 1036.58 Hz \end{array}$

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