translate the following MIPS code to C. Assume that the variables i, j, and k are assigned to the registers $s0, $s1, and $s2, respectively. Assume that the base address of the array A is in registers $s6. Loop: blt $s0, $s1, Exit bge $s1, $s2, Exit addi $s1, $s1, 5 j Loop Exit: addi $t0, $zero, 4 ble $s0, $t0, Done sll $t1, $s0, 2 add $t2, $s6, $t1 sw $zero, 0($t2) Done:
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translate the following MIPS code to C. Assume that the variables i, j, and k are
assigned to the registers $s0, $s1, and $s2, respectively. Assume that the base
address of the array A is in registers $s6.
Loop: blt $s0, $s1, Exit
bge $s1, $s2, Exit
addi $s1, $s1, 5
j Loop
Exit:
addi $t0, $zero, 4
ble $s0, $t0, Done
sll $t1, $s0, 2
add $t2, $s6, $t1
sw $zero, 0($t2)
Done:
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