To solve the nonlinear inequalityx + :< 0, we first observe that the numbers(smaller value) and(larger value) are zeros of the numerator and denominator. These numbersdivide the real line into three intervals. Complete the table.(-a,IntervalSign of x + 1? vSign of x - 4Sign of (x + 1)/(x – 4)Do any of the endpoints fail to satisfy the inequality?O YesO NoIf so, which one(s)? (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.)Find the solution of the inequality. (Enter your answer using interval notation.)

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To solve the nonlinear inequality X+1s 0, we first observe that the numbers |(smaller value) and (larger value) are zeros of the numerator and denominator. These numbers divide the real line into three intervals. Complete the table. (-∞, (C Interval Sign of x + 1 Sign of x - 4 Sign of (x + 1)/(x - 4) Do any of the endpoints fail to satisfy the inequality? O Yes O No If so, which one(s)? (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) Find the solution of the inequality. (Enter your answer using interval notation.)