To recall, the formula for solving the electric field and electric potential in electrostatic equilibrium is as follows: A. Point is inside the conductor (r > d): Electric Field = 0 Electric Potential = ka/r B. Point is outside the conductor (r< d): Electric Field = kQ/d Electric Potential = KQ/a C. Point is on the surface of the conductor (r = d) Electric Field = KQ/r Electric Potential - ka/r TEST CASES: If the rd; Enter charge (Q): 20 Enter the radius of the spherical conductor (r): 500 Enter the distance of the point from the center (d): 60 The electric field is 0 V/m and the electric potential is 360 000 000 v.

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To recall, the formula for solving the electric field and electric potential in
electrostatic equilibrium is as follows:
A. Point is inside the conductor (r > d):
Electric Field = 0
Electric Potential = kQ/r
B. Point is outside the conductor (r< d):
Electric Field = kQ/d
Electric Potential = KQ/d
C. Point is on the surface of the conductor (r = d)
Electric Field = kQ/r
Electric Potential = ko/r
TEST CASES:
If the r<d:
Enter charge (Q): 0.4
Enter the radius of the spherical conductor (r): 5
Enter the distance of the point from the center (d): 60
The electric field is 1000000 V/m and the electric potential is 60 000 000 V.
If the r> d:
Enter charge (Q): 20
Enter the radius of the spherical conductor (r): 500
Enter the distance of the point from the center (d): 60
The electric field is 0 V/m and the electric potential is 360 000 000 V.
Transcribed Image Text:To recall, the formula for solving the electric field and electric potential in electrostatic equilibrium is as follows: A. Point is inside the conductor (r > d): Electric Field = 0 Electric Potential = kQ/r B. Point is outside the conductor (r< d): Electric Field = kQ/d Electric Potential = KQ/d C. Point is on the surface of the conductor (r = d) Electric Field = kQ/r Electric Potential = ko/r TEST CASES: If the r<d: Enter charge (Q): 0.4 Enter the radius of the spherical conductor (r): 5 Enter the distance of the point from the center (d): 60 The electric field is 1000000 V/m and the electric potential is 60 000 000 V. If the r> d: Enter charge (Q): 20 Enter the radius of the spherical conductor (r): 500 Enter the distance of the point from the center (d): 60 The electric field is 0 V/m and the electric potential is 360 000 000 V.
PROBLEM:
Write a program that computes for the Electric Field and Electric Potential at a given point in a spherical
conductor with a radius (r) and a charge a, depending upon the following cases:
Calculate the electric field and electric potential at:
A.
d<r
B.
d>r
C.
d =r
SPECIFICATIONS:
- The program will depend on the input parameters to determine which case to use in computing for the
electric field and electric potential at different points:
Point is inside the conductor (d <r)
• Point is outside the conductor (d > r)
• Point is on the surface of the conductor (d = r)
- The user will input the charge Q, the radius of the conductor (r) and the distance of the point from the
center (d)
- The constant k = 9x1019 = 9000000000
- The program will provide an output for the electric field (V/m) and for the electric potential (V)
- All lines of codes should have a comment/pseudocode.
Transcribed Image Text:PROBLEM: Write a program that computes for the Electric Field and Electric Potential at a given point in a spherical conductor with a radius (r) and a charge a, depending upon the following cases: Calculate the electric field and electric potential at: A. d<r B. d>r C. d =r SPECIFICATIONS: - The program will depend on the input parameters to determine which case to use in computing for the electric field and electric potential at different points: Point is inside the conductor (d <r) • Point is outside the conductor (d > r) • Point is on the surface of the conductor (d = r) - The user will input the charge Q, the radius of the conductor (r) and the distance of the point from the center (d) - The constant k = 9x1019 = 9000000000 - The program will provide an output for the electric field (V/m) and for the electric potential (V) - All lines of codes should have a comment/pseudocode.
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