To recall, the formula for solving the electric field and electric potential in electrostatic equilibrium is as follows: A. Point is inside the conductor (r > d): Electric Field = 0 Electric Potential = ka/r B. Point is outside the conductor (r< d): Electric Field = kQ/d Electric Potential = KQ/a C. Point is on the surface of the conductor (r = d) Electric Field = KQ/r Electric Potential - ka/r TEST CASES: If the rd; Enter charge (Q): 20 Enter the radius of the spherical conductor (r): 500 Enter the distance of the point from the center (d): 60 The electric field is 0 V/m and the electric potential is 360 000 000 v.
To recall, the formula for solving the electric field and electric potential in electrostatic equilibrium is as follows: A. Point is inside the conductor (r > d): Electric Field = 0 Electric Potential = ka/r B. Point is outside the conductor (r< d): Electric Field = kQ/d Electric Potential = KQ/a C. Point is on the surface of the conductor (r = d) Electric Field = KQ/r Electric Potential - ka/r TEST CASES: If the rd; Enter charge (Q): 20 Enter the radius of the spherical conductor (r): 500 Enter the distance of the point from the center (d): 60 The electric field is 0 V/m and the electric potential is 360 000 000 v.
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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