Three resistors in parallel: RTotal 1 1 1 1 + + R₁ R2 R3 1) The circuit in figure (1) has, Vsupply =40 Volts, R₁ = 300 and R₂= 60 Q. a) Calculte the total resistor for this parallel circuit. RTotal = b) Calculata l₁ and 12, and verfy if ITotal =11+1₂=_ c) Calculate the total current for this circuit. Total = Vsupply Figure (1) w R2

Three resistors in parallel: RTotal 1 1 1 1 + + R₁ R2 R3 1) The circuit in figure (1) has, Vsupply =40 Volts, R₁ = 300 and R₂= 60 Q. a) Calculte the total resistor for this parallel circuit. RTotal = b) Calculata l₁ and 12, and verfy if ITotal =11+1₂=_ c) Calculate the total current for this circuit. Total = Vsupply Figure (1) w R2

Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter7: Parallel Circuits

Section: Chapter Questions

Problem 3PP: Using the rules for parallel circuits and Ohmslaw, solve for the missing values....

See similar textbooks

Similar questions

Using the rules for parallel circuits and Ohmslaw, solve for the missing values. ETE1E2E3E4ITl1I2l33.2AI4RT3.582R116R210R3R420PTP1P2P3P4
With V1, voltage peak to peak is 10 volts, R1=200 Ohm, R2=1000 Ohm and C1= 300 nF. Find Vx, voltage across the the capacitor, C1 and R2 when the frequency is 1000 Hz and 10000 Hz
In the circuit in the figure, the amplitude of the input current is 5 Amps and its phase is 0 degrees, the amplitude of the input voltage is 18 volts and its phase is 90 degrees. How many volts is the amplitude of the voltage phasor V on capacitor C1? Values of the elements in the circuit:R= 14 OhmsC1= 10j OhmsC2= -3j OhmsL= 4j Ohms
Current Attempt in Progress In the figure R₁ = R₂=4.502, R3-7.202, R4 3.80, R5 1.302, and R6 R7 Rg=8.802, and the ideal batteries have emfs 1 = 26 V and 82-8.3 V. What are the (a) magnitude and (b) direction (up or down) of current is and the (c) magnitude and (d) direction of current i2? What is the energy transfer rate in (e) battery 1 and (f) battery 2? Is energy being supplied or absorbed in (g) battery 1 and (h) battery 2? (a) Number i (b) (c) Number (d) O (e) Number i (8) O (f) Number i (h) O O R₁ R₂ www R₂ R₂ Ro Units Units Units Units ww www R₂ R₁ 4 8,0 342 R₂ O O
Determine the currents IR1 and IR2, (show as positive values – actual current direction). Verify in Multisim using measurement probes or digital multimeter
If a circuit has a resistance of 3002 and a series inductance of 5002, what is the relationship between the applied circuit voltage and the circuit current? The applied voltage lags the circuit current. The phase shift between the circuit voltage and current changes with time. The applied voltage is in phase with the circuit current. The applied voltage leads the circuit cur Previous Page Next Page Page 2 of 10
Determine the DC currents (IB, Ic and lĘ) and dc junction voltages (VBE, VCE and VCB) Ig=Blank 1 mA, Ic=Blank 2 mA, IĘ=Blank 3 mA, VBE= Blank 4 V, VCE = Blank 5 V and VCB = Blank 6 V Use 2 decimal places. Use the following values: VBB = 2V RB = 7 kQ Rc = 248 Q Vcc = 19 V BDc = 56 Blank 1 Add your answer Blank 2 Add your answer Blank 3 Add your answer Blank 4 Add your answer Blank 5 Add your answer Blank 6 Add your answer
If the voltage V, = 800 mV, then the current flowing in the load I, is: %3D -j20n Select one: O a. None of these O b. Is 100 <-90° mA O c. Is 5.0<.-90° A O d. Is 5 <90° mA ell
The voltage across the resistor in series RL when suddenly supplied by a DC source is? a. zero O b. minimum O c. infinity O d. maximum
Subject: CircuitsGivenRt = 37.9529 ohm..Rcd = 3.6 ohm.Rab=2.3529ohmIt=1.58APt=94.85WV2=3.16VV4=6.32VVab=3.7175vVcd=5.688VI10=0.372AI5=0.7435AI8=0.465AI9=0.632AI6=0.348AP2=4.9928WP4=9.9856WPab=5.88WP14=34.95WPcd=8.99WP12=29.96W
What is the function of the circuit shown in Figure 9? CLR CLK (9) (8) (2) R PR (3) lo S bHR Q₁ S bR bR (5) Q₂ S Figure 9 (6) 23 S PR (10) 24 PR (11) Q5 S PR (12) 26 S (13) 27
Determine the DC currents (la. lc and I) and dc junction voltages (Var Ver and Vca) la-Blank 1 mA, le-Blank 2 mA, I-Blank 3 mA, Var Blank 4 V, Vcr Blank 5 V and VcB - Blank 6 V Use 2 decimal places. Use the following values. VBB= 3V RB= 5kOhms Rc=232 ohms Vcc =18 V BDC=65