Three charged particles are at the corners of an equilateral triangle as shown in the figure below. (Let q = 2.00 μC, and L = 0.650 m.)7.00 μC960.0⁰L-4.00 μC(a) Calculate the electric field at the position of charge q due to the 7.00-µC and -4.00-µC charges.106.51XOnce you calculate the magnitude of the field contribution from each charge you need to add these as vectors. kN/C Î + 149.1You have given the magnitude of the field due to the 7.00-μC charge. What is the y component of this field? kN/C ĵ(b) Use your answer to part (a) to determine the force on charge q.mNÎ +mN ĴX

Electric field due to a point charge q at a distance r from point charge is given bydirection of…

Answered: Three charged particles are at the…

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter25: Gauss’s Law

Section: Chapter Questions

Problem 49PQ

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The electric field 10.0 cm from the surface of a copper ball of radius 5.0 cm is directed toward the ball's center and has magnitude 4.0102 N/C. How much charge is on the surface of the ball?
The figure below shows three charged spheres arranged along the y axis. (Assume 91 = 75.0 cm 22.0 cm 91 –4.80 μC 92 X (a) What is the electric field at x = N/C = 0, y = 3.50 m? (b) What is the electric field at x = 3.50 m, y = 0? Z N/C 2.70 μC and 92 = 4.15 μC. Express your answers in vector form.)
The point charges in the figure below are located at the corners of an equilateral triangle 25.0 cm on a side, where qp = +13.0 µC and g. -6.75 µC. (Assume that the +x-axis is directed to the right.) la (a) Find the electric field at the location of qa. magnitude N/C 60 direction In what direction does an electric field that is created by a negative charge point?° (counterclockwise from the +x-axis) (b) What is the force on ga, given that qa = +1.50 nC? magnitude N 59.98 What sides of the triangle are given by the electric field in the x and y directions?° (counterclockwise from the +x-axis) direction
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Three charged particles are at the corners of an equilateral triangle as shown in the figure below. (Let q = 2.00 μC, and L = 0.800 m.) 7.00 μC y 60.0⁰ 9 L -4.00 μC (a) Calculate the electric field at the position of charge q due to the 7.00-μC and -4.00-μC charges. -21.1 X Once you calculate the magnitude of the field contribution from each charge you need to add these as vectors. kN/C Î + (b) Use your answer to part (a) to determine the force on charge q. mNÎ + mN î KN/Cĵ
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Two parallel plates carry charge of equal magnitude but opposite sign, and are separated by a distance of d = 16.0 cm. Each plate has a uniform surface charge density of ± ? = 40.0 nC/m2. (Please enter all answers using at least four significant figures.) (a.) Determine the magnitude of the electric field between teh plates from the charge density. (Recall, from chapter 23, the magnitude of the uniform electric field between two parallel, charged plates is E = ?/?o.) (b.) If a proton ( q = e = 1.602 ✕ 10-19 C; mp = 1.673 ✕ 10-27 kg) is released from rest at the positive plate, what potential difference does it move through in reaching the negative plate? (c.) What is the change in potential energy of the system when the proton is accelerated from the positive to the negative plate? (d.) Determine the speed of the proton just before it strikes the negative plate (if it is accelerated from rest from the positive plate).
Three charged particles are at the corners of an equilateral triangle as shown in the figure below. (Let q = 2.00 μC, and L = 0.550 m.) q: 7.00 με y 60.0° L 9 - x -4.00 μC (a) Calculate the electric field at the position of charge q due to the 7.00-μC and -4.00-μC charges. Once you calculate the magnitude of the field contribution from each charge you need to add these as vectors. KN/C 1 + Does the -4.00-μC charge contribute to the y component of the field at the origin? KN/C ĵ (b) Use your answer to part (a) to determine the force on charge q. If you know the electric field at a particular point, how do you find the force that acts on a charge at that point? mN I + Check units carefully. Note that the field in part (a) is given in kN/J and the force in this part is given in mN. mNĵ x
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Three point charges are located at the corners of an equilateral triangle with sides of 3.26 cm as shown below. What is the x (horizontal) component of the electric field at the position of charge qa if qb= 6.04×10-¹²℃ and qc = 5.26×10-¹2C? Assume 3 sig figs. You do not need to use scientific notation. O qc qa qb
Three charged particles are at the corners of an equilateral triangle as shown in the figure below. (Let q = 3.00 μC, and L= 0.850 m.) 7.00 μ. 60.0⁰ 9 L -4.00 με Φ (a) Calculate the electric field at the position of charge q due to the 7.00-μC and -4.00-μC charges. Once you calculate the magnitude of the field contribution from each charge you need to add these as vectors. KN/C Î + Think carefully about the direction of the field due to the 7.00-μC charge. kN/Cj (b) Use your answer to part (a) to determine the force on charge q. x If you know the electric field at a particular point, how do you find the force that acts on a charge at that point? mNÎ + If you know the electric field at a particular point, how do you find the force that acts on a charge at that point? mN ĵ
A positive test charge of magnitude 0.05µC is placed at the point P. If the point P is located 20 cm to the left of an 10µC charge what is the magnitude and direction of the electric field at P. Recall that k = 8.99 x 10° Nm²c² O a. 4495000.00 N/C, to the left O b. 224.75 N/C, to the left O c. 4.5e5 N/C, to the right O d. 2.2e6 N/C, to the left arch WE

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