Three cell membrane samples: M, C, and S were fluorescently labeled and were subsequently photobleached. The recovery of fluorescence was monitored and gave the following profile: 100 M C time a. Rank the three cell membranes in terms of decreasing fluidity. Provide an explanation of your ranking based on their FRAP curves and the most probable appearance and composition of the three membranes. b. Draw the expected image of the surface of the three membranes before photobleaching and after fluorescence recovery as viewed under a fluorescence microscope. % fluorescence
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- 3 cell membrane samples: A, B, and C were fluorescently labeled and subsequently photobleached. The recovery of fluorescence is given on the FRAP curve: (see image attached) Rank the 3 cell membranes in terms of DECREASING fluidity and explain your ranking based on: their FRAP curves; most probable appearance; and most probable composition of the membranesGiven the following summary of the two microscopes, identify the microscope to be used in these scenario: 1. An image with 18x actual magnification and an apparent size of 1.04mm 2. Unknown specimen that is 0.435 angstrom 3. A microorganism with 2.1 nm size *show solution and brief explanationDesign an experiment to study the effect of solvent on the integrity of the membrahe of carrot-root cells. Remember that carrot contains carotenoids which include the yellow-orange colored pigments which can be collectively measured by a spectrophotometer at 450 nm. Also remember that these group are fat soluble. State your hypothesis, a brief summary of the experimental procedure and conditions, the expected outcome(s) and conclusion(s)
- Indicate the contrast statements of the following chromatographic techniques of separation. A. A separation of components mixture based on migration rates in a stationary phase by a gaseous or liquid mobile phase. B. The supported materials coated of flat plate or in fibres of paper stationary phase is known as planar chromatography. C. The rate of migration of molecules or analytes is depending on the relative solubility of the solute in the stationary phase and mobile phase. D. Involve an electronic transition of valence shell electron in free atoms to provide analytical information about sample composition.Average skin (epidermal) cell has a diameter of 30 micrometers. The majority of the surface of the human body is covered by skin cells. The average surface area of an adult male is 1.9 m2 and an adult female is 1.6 m2. 1. Use this formula to determine the area an average skin cell covers: Area = π (radius)2 Plug the radius (1/2 the diameter) of an average skin cell into the equation. area of an average skin cell ____________________ 2. Next, convert your surface area (average male or female) from m2 into mm2 your surface area____________________ 3. Then, divide your surface area by the average area of a skin cell. number of skin cells covering your body ____________________With regard to the spectrophotometer, which of the following is true for regarding the term absorbance? I. The term refers to the amount of light that is prevented from passing through a solution. II. As solute concentration increases the absorbance reading also increases. III. Absorbance is the opposite of transmittance.
- The reults for the macroscopic part: 0.30M glycerin – solution was translucent (could see text behind the test tube) 0.15M NaCl – solution was opaque (could not see text behind the test tube) 0.30M NaCl – solution was opaque (could not see text behind the test tube) 0.15M glucose – solution was translucent (could see text behind the test tube) 0.30M glucose – solution was opaque (could not see text behind the test tube) 0.30M Urea – solution was translucent (could see text behind the test tube) Results for microscopic part: 0.30M glycerin – no cells present 0.15M NaCl – normal sized cells 0.30M NaCl – crenated (shrunken and star-shaped) cells 0.15M glucose – no cells present 0.30M glucose – normal sized cells 0.30M Urea – no cells present Determine the osmolarity (hypoosmotic, isosmotic, or hyperosmotic) and tonicity (hypotonic, isotonic, hypertonic) of the following solutions.In which solutions did the osmolarity NOT match the tonicity? For those solutions, why did the osmolarity…Given the information provided, please answer the following question: Volume of cell suspension needed (for 5 x 104 cells): __________________microliters (µL)Discussion Give the main differences between the types of microscopes used to diagnose surfaces?) What is the appropriate device to diagnose each of the following and why? O A- The aluminum plate is coated with a nano-solution. b- A colloidal sample containing nano-solutions. C- Study of the microstructure of the surface of a sample of iron.' Is it possible to use an optical microscope to study painted metal) surfaces? And why?
- You have a microscope equipped with 10 x oculars and 4 objectives, which exhibit the following characteristics (M, NA): A=(4 x/0.13); B=(20 x/0.4); C=(20 x/0.7); D=(40 x/0.65) Tick the right answers: o Objectives B and C are equivalent. o Objective D will allow more detailed observation than objective C. o To see small structures, you should choose objective D rather than C. o Objective D has a lower resolution than objective C. o To observe large objects, it is better to use objective B rather than objective CL of Microscopes: 1. If you have a standard ocular lens of 10x what is the true magnification that you are looking at if you are using the 100x objective lens. What is the rule for focusing if you switch to the 40x lens? 2. Calculate the sizes of the following cells. Not all cells are viewed at 40x so use the following table to calculate the size of your cells. 4x 1 reticular unit = .025 mm 10x 1 reticular unit = .01 mm 40x 1 reticular unit-.0025 mm 4 points A) Cell 1 on 10x=8 reticular units B) Cell 2 on 40 x = 28 reticular units mm mm Which one is actually larger? Which one is probably the plant cell? Why?Ms. Sassa, a biology professor, wanted to demonstrate to her students the applicability of a dialyzing membrane (DM) as a model for the cell membrane by enclosing an aqueous solution in a DM bag and immersing in a beaker containing a different solution. Substances available which are permeable to the DM include 0.02 M NaCl, 0.03 M glucose, and 0.01 M glucose. The only substance available which is completely impermeable to the DM is the 0.01 M lactose. Using the substances given and materials such as a beaker, stirring rod, and string, draw ONLY ONE set-up that can be demonstrated by Ms. Sassa that will satisfy ALL of the following conditions: a. No solute will exhibit a net diffusion out of the cell. b. Glucose will exhibit a net diffusion into the cell. c. NaCl will exhibit a zero net movement. d. No net movement of lactose from the inside to outside of the cell. Make sure to label properly the substance inside the beaker and inside the DM bag.