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- H. N- imert) waib)omoatosib owl to erit waib) aemoaloanate ow io H H 12 ( k) CH;NHCH,OCH;CONHCH3 houulifanoo yam as wsid (e1eoet lenonulanos o) leulocR en H. H. c=Ć-C- H. нно о H. онн rplugelomiclinos ns bas lSo 0 H. нн H. H. H H- H-Ć H HNH N H -H H. H. (! H H. H---H H H H. H H H-C-C-C=C-C-C-H HHH H---S-5-5--H H H f) (CH3CH2O)2CO CH3COCH2CO2CH3 b) CH;CHBr(CH2)¿CH(CH3)2 a) CH3(CH2)3CH3 CH3CHCHCH2CHCH2 (CH3)3CCH2CH3 STEREOCHEMISTRY 1. Convert the following condensed and Lewis structures into line-angle structuresc) Study the following reaction scheme for the preparation of a natural glycoside (compound 7) and answer the questions that follow: OH OAc Но excess Ac20 AcO pyridine, 0°C HO- Но. AcO- -OAc `0Ac HO Compound 3 Compound 4 HBr OCH3 OAc OAc AcO' AcO AcO AcO- OAc OAc Compound 6 Compound 5 Br NaOH, H2O OCH3 Он HO НО Compound 7 ii. Identify the unknown reagent(s) in the reaction scheme which converts compound 5 to compound 6.5. which of the following compaunds wendd be more sin th. eguilibrium (*aplain tha rentu e) HC f) 3) "C R 14 R= CH3 CH2 CH2
- when Mg(03 is heated is Prauces Mg0 aus Co, iF 5-0g af magms ivm. Carbomate is heated aud only 3-65g af magnesivm Gxide is formes> whetis the percent yeild 24. Write the equation for the saponification of the triacylglycerol: сн,-0-со-CHg 35 ÇH-O-CO-CH;s CH, -0-со-С,н +NaOH ҫH-0-Со-С1-Н;;(8) + он он H30+ H NaоH, H₂0 25° C NAOH catalytic amount
- (Thanks for the help if you can break down the steps and provide drawings(needed) during the answer since i am trying to see if i have solved this in the right way not copy :)) Draw the heme environment in oxymyoglobin and explain how the geometric data for the attached oxygen molecule may be understood. Fe O (bond length) = 1.809 Å; O-O (bond length ) = 1.246 Å; Fe - O - O (bond angle) = 123 \deg12:08 PM Thu Apr 28 @ 61% HW 13 Home Insert Draw Layout Review View Calibri Light Regu 12 ΒΙυ U A unsaturated b. -C(CH,),CH=CH(CH,),CH3 8ölid С. || -C(CH,)16CH; Saterated 54. Classify each of the following carbohydrates as a monosaccharide, dissaccharide, or polysaccharide: CH,OH H 0- н СН,ОН 0 H а. H ОН Н H OH НО CH,OH OH ОН H H H-C-0H НО—С—Н H-C-OH Н—С—ОН CH,OH HOCH2 CH,OH С. H. Но OCH2CH3 OH H CH,OH CH,OH CH,OH H -0 H H -0 H H H d. H. ОН Н ОН Н ОН Н ОН H OH H ОН 58. Classify each molecule as a lipid, carbohydrate, or amino acid: CH,0C(CH,)12CH, а. l'pid CHOC(CH,),4CH3 CH;0C(CH,),CH=CH(CH,);CH; b.( Based on the fomal chorges, uhich Structure is 0- =N (I calcute the fomal chargeo (II) O=)=N (-N00) uol Below are three possible structures for the cyanate 6.
- Isoleucine, another of the twenty amino acids found in proteins, is metabolized by a pathway that includes the following step. Propose a mechanism.Hemoglobin has pI=6.8. Does hemoglobin have a net negative charge or net positive charge at pH=5.3? At pH=7.3?6, The structure originelly proposed For Cordycepic acid, [a] +40.3°, has been + 40.3°, has been shown to be in Correct, suggest to be reason skeptical obout the original Structure, which is given below CO2H 1.29 HO HO.
