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- iven the following sorted vector of integers: // index 0 1 2 3 4 5 6 7 8 9 10 11 12 13vector<int> v {-23, -5, 9, 14, 15, 18, 23, 24, 25, 27, 34, 62, 85, 87}; What indexes are examined in a search for each value, and what value is returned? sequential search for 27 A examines 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13; returns 9 B examines 0, 1, 2, 3, 4, 5, 6, 7, 8, 9; returns 27 C examines 0, 1, 2, 3, 4, 5, 6, 7, 8, 9; returns 9 D examines 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13; returns 27 E examines 13, 12, 11, 10, 9; returns 9 (order shuffled) binary search for 27 A examines 6, 8, 10; returns 9 B examines 6, 10, 8, 9; returns 9 C examines 6, 9; returns 9 D examines 6, 3, 1; returns -1 E examines 7, 10, 9; returns 9 (order shuffled)Given are a 5x6 matrix A, a 3 x 6 matrix B, and a 9-element vector v. 25 8 11 14 17 5 10 15 20 25 30 30 35 40 45 50 55 55 60 65 70 75 80 B = 3 6 9 12 15 18 47 10 13 16 19 5 8 11 14 17 20 69 12 15 18 21 A = 99 98 97 96 95 94 93 92 91 y = Create the three arrays in the Command Window, and then, by writing one com- mand, replace the last four columns of the first and third rows of A with the first four columns of the first two rows of B, the last four columns of the fourth row of A with the elements 5 through 8 of v, and the last four columns of the fifth row of A with columns 3 through 5 of the third row of B.This code is for Guass Siedel itrations, There are many syntex errors in this code, anybody can remove the syntex errors? A = np.array([[10., -1., 2., 0.], [-1., 11., -1., 3.], [2., -1., 10., -1.], [0., 3., -1., 8.]]) # initialize the RHS vector b = np.array([6.0, 25.0, -11.0, 15.0]) print("System of equations:") for i in range(A.shape[0]): row = ["{0:3g}*x{1}".format(A[i, j], j + 1) for j in range(A.shape[1])] print("[{0}] = [{1:3g}]".format(" + ".join(row), b[i])) x = np.zeros_like(b) for it_count in range(1, ITERATION_LIMIT): x_new = np.zeros_like(x) print("Iteration {0}: {1}".format(it_count, x)) for i in range(A.shape[0]): s1 = np.dot(A[i, :i], x_new[:i]) s2 = np.dot(A[i, i + 1 :], x[i + 1 :]) x_new[i] = (b[i] - s1 - s2) / A[i, i] if np.allclose(x, x_new, rtol=1e-8): break x = x_new print("Solution: {0}".format(x)) error = np.dot(A, x) - b print("Error: {0}".format(error))
- Write a code in “C” that can create a [n×m] dimensional matrix. Take the values of all the elements from the user.%Encode A1, b1 and x1 as the vector of unknowns. A1 = b1 = syms xv1 = %Check the size of A, set it as m1 and n1 [m1,n1] = %Augment A and b to form AM1 AM1 = %Solve the Reduced Rwo Echelon of AM1. RREFA1 = %Collect the last column and set as bnew1, set the remaining elements as Anew1 bnew1= Anew1 = %Check if Anew is an identity matrix, if it is, bnew is the solution if Anew1 =eye(m1,n1) Root1 = bnew1 else display("No Solution") end %Augment the matrix A1 with the identity Matrix of the same size, set the result as AMI1 AMI1 = %Find the reduced row echelon form of AMI1, set the result as RREFAI1 RREFAI1= %Collect the second half of the matrix as AInew1, set the remaining elements as AIold1 AInew1= AIold1 = %Check if AIold1 is an identity matrix, if it is, AInew1 is the inverse %Encode A2, b2 and xv2 as the vector of unknowns. A2 = b2 = syms xv2 = %Check the size of A2, set it as m2 and n2 [m2,n2] = %Augment A2 and b2 to form AM2 AM2 = %Solve the…Java code: write a java code that can perform SQUARE-MATRIX-MULTIPLY-RECURSIVE. A; B(Strassen's Algorithms)/ and ordinary multiplication. The program should ask the user for input file and output file locations, and give output for both methods. It should also check if both outputs match and include error handing for incorrect Matrix Multiplication input.
- The file week12.py contains a matrix-valued function, f. More specifically, given any float x, the value f(x) returned by this function is a square Numpy array. There exists exactly one value x in the interval (-10,10) for which the matrix f(x) is singular. Print this value correct to exactly 10 decimal places.Function PrintArray(integer array(?) dataList) returns nothing integer i for i = 0; i < dataList.size; i = i + 1 dataList[i] = Get next input Put dataList to output Put "_" to output // Your solution goes here. Modify as needed i = 0 Complete the PrintArray function to iterate over each element in dataList. Each iteration should put the element to output. Then, put "_" to output. Ex: If dataList's elements are 2 4 7, then output is: 2_4_7_ Function Main() returns nothing integer array(3) userNums integer i for i = 0; i < userNums.size; i = i + 1 userNums[i] = Get next input PrintArray(userNums)2. Replace the even locations in the vector m= [7 9 2 4 5 8 10 3] with the following set of elements [1036 7] Your answer
- The formula C=numpy.add(A, B) adds the two matrices A and B and stores the result in C.• To subtract matrix B from matrix A, enter C=numpy.subtract(A, B). The result is stored in C.• C=numpy.divide(A, B): Split matrix A into two equal parts and store the result in C.• C stands for numpy.multiply(A, B): Multiply matrices A and B, then store the result in matrices C.• C=numpy.sum(A): Calculate the sum of each element in the matrix A, then store the result in c R.• C=numpy.sum(A, axis = 0): Create a vector C by adding the columns of the matrix A.• C=numpy.sum(A, axis = 1): Summarize matrix A row-by-row and store the result in the vector C. Create Python code that demonstrates the use of these techniques in a sample matrix.NumPy includes a submodule numpy.linalg where many functions are defined to allow the user to do various things related to linear algebra. If A is a square matrix represented as an object of type ndarray , the function eigvals () will return the eigenvalues of A as an array. Which of the following code snippets would correctly import the module and call this function with the matrix (A as input? Note: There may be more than one correct answer! Select all that will work.The code for a function that is similar tofunction vfunct (a). We used vfunct toillustrate the use of a frame pointer in managing variable-sizestack frames. The new function aframe allocates space forlocal(a) C code1 #include <alloca.h>23 long aframe(long n, long idx, long *q) {4 long i;5 long **p = alloca(n * sizeof(long *));6 p[0] = &i;7 for (i = 1; i < n; i++)8 p[i] = q;9 return *p[idx];10 }(b) Portions of generated assembly codelong aframe(long n, long idx, long *q)n in %rdi, idx in %rsi, q in %rdx1 aframe:2 pushq %rbp3 movq %rsp, %rbp4 subq $16, %rsp Allocate space for i (%rsp = s )5 leaq 30(,%rdi,8), %rax6 andq $-16, %rax7 subq %rax, %rsp Allocate space for array p(%rsp = s )8 leaq 15(%rsp), %r89 andq $-16, %r8 Set %r8 to &p[0]⋮array p by calling library function alloca . This function issimilar to the more commonly used function malloc, except thatit allocates space on the run-time stack. The space isautomatically deallocated when the executing…