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The voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasing as the resistor heats up. Use Ohm's law, V = IR, to find how the current I is changing (in A/s) at the moment dv dR when R = 314 , I = 0.09 A, = -0.02 V/s, and = 0.06 0/s. (Round your answer to six decimal places.) dt dt A/s Need Help? Read It

The voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasing as the resistor heats up. Use Ohm's law, V = IR, to find how the current I is changing (in A/s) at the moment dv dR when R = 314 , I = 0.09 A, = -0.02 V/s, and = 0.06 0/s. (Round your answer to six decimal places.) dt dt A/s Need Help? Read It

Algebra for College Students
Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter10: Exponential And Logarithmic Functions
Section10.CT: Test
Problem 21CT
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The voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasing as the resistor heats up. Use Ohm's law, V = IR, to find how the current I is changing (in A/s) at the moment when R = 314 0,1 = 0.09 A, V = -0.02 V/s, and dR = 0.06 n/s. (Round your answer to six decimal places.) dt dt A/s Need Help? Read It
Transcribed Image Text:The voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasing as the resistor heats up. Use Ohm's law, V = IR, to find how the current I is changing (in A/s) at the moment when R = 314 0,1 = 0.09 A, V = -0.02 V/s, and dR = 0.06 n/s. (Round your answer to six decimal places.) dt dt A/s Need Help? Read It
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