The velocity of a stone thrown upward with a velocity of 12.0 m/s in a medium that has resistance is given by the differential equation dv = (-9.81 m/s²) – (1.00/s) v dt before it reaches the ground. At what time after it was thrown will it reach its maximum height? Answer: seconds (3 decimal

The velocity of a stone thrown upward with a velocity of 12.0 m/s in a medium that has resistance is given by the differential equation dv = (-9.81 m/s²) – (1.00/s) v dt before it reaches the ground. At what time after it was thrown will it reach its maximum height? Answer: seconds (3 decimal

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter1: Units And Measurement

Section: Chapter Questions

Problem 33P: In SI units, speeds are measured in meters per second (m/s). But, depending on where you live,...

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Distance and Speed

The speed, distance and time relation forms the basis of study of motion. You will need these concepts in the study of Mechanics. This concept is applicable for students who are studying the following courses –

Question

Applications of the first-order Differential Equations

The velocity of a stone thrown upward with a
velocity of 12.0 m/s in a medium that has
resistance is given by the differential equation
dv
(-9.81 m/s²) – (1.00/s) v
dt
before it reaches the ground. At what time
after it was thrown will it reach its maximum
height?
Answer:
seconds (3 decimal
places)

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